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\[

A.\dfrac{1}{3} \\

B.\dfrac{5}{6} \\

C.\dfrac{1}{2} \\

\]

D. None of these

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We are asked to find the probability of getting a composite or non prime number when we throw a dice.

When we throw a dice, the number of outcomes which are possible are \[6\].

The sample space \[S\] of the event is\[\left\{ {1,2,3,4,5,6} \right\}\].

There are 2 composite or non prime numbers in the sample space which are \[\{ 4,6\} \].

So, the number of favourable outcomes which are possible \[ = 2\]

Let \[A\] be the event of getting composite numbers when we throw a dice.

So, the probability of getting composite numbers when we throw a dice

\[

= P(A) \\

= \dfrac{{n(A)}}{{n(S)}} \\

= \dfrac{2}{6} \\

= \dfrac{1}{3} \\

\]

\[n(A)\& n(S)\]are the cardinal numbers of the event of getting composite numbers when we throw a dice and the sample space respectively.

Therefore, the probability of getting a composite number on throwing a dice is \[\dfrac{1}{3}\].