Question

The phase difference between A and C in the wave as shown in the figure is

$\begin{align}
  & A.0rads \\
 & B.\pi rads \\
 & C.\dfrac{\pi }{2}rads \\
 & D.2\pi rads \\
\end{align}$

Answer 1

Hint: Phase Difference is helpful in describing the differences in degrees or radians when two or more alternating quantities reach their maximum or minimum values. As we know that a sinusoidal waveform is an alternating quantity that is able to be presented graphically in a time domain along a horizontal zero axis.

Complete step by step answer:
A phase variation sometimes happens when a wave is being reflected. Such reflections happen for many types of wave, which includes light waves, sound waves, and the waves on the strings. And the path difference can be abbreviated as PD is the difference in the distance traversed by the two waves from their respective sources to a given point on the pattern. If one of the two sound waves of the similar frequency is shifted by one-half cycle relative to the other wave, then the sound waves are declared to be in “out of phase.” Two waves that are being out of phase exactly cancel each other when they are added together.
The particles at A and C are in vibration with opposite directions, hence they are out of phase. The phase difference between these two points will be \[\dfrac{\pi }{2}\]. Hence the correct answer is option C.

Note:
For a point on the first antinodes, the path difference is equal to one wavelength. Destructive interference happens if the maxima of two waves are 180 degrees out of phase. A positive displacement of one wave is cancelled out by a negative displacement in the other wave. Therefore the amplitudes of the resulting wave will be zero. If two sound waves that are in the same phase which is added to create a sound wave of larger amplitude.