
The perimeters of two similar triangles are $30cm$ and $20cm$ respectively. If one side of the first triangle is $12cm$, determine the corresponding side of the second triangle.
Answer
616.8k+ views
Hint: Here we will apply the property of similar triangles i.e., “Ratio of corresponding sides of similar triangles is equal to the ratio of their perimeters” to determine the corresponding side of the second triangle.
Complete step-by-step answer:
According to the given data, let us consider
$\Delta ABC$ as the first triangle with the perimeter ${P_1}$.
$\Delta DEF$ as the second triangle with the perimeter ${P_2}$.
Here the triangles $\Delta ABC$ and $\Delta DEF$ are similar triangles.
Given that,
One side of the first triangle is$12cm$, which means $AB = 12cm$($\because $ $\Delta ABC$ is the first triangle).
$
{P_1} = 30cm \\
{P_2} = 20cm \\
$
Since the triangles given are similar triangles.
We know that “Ratio of corresponding sides of similar triangles is equal to the ratio of their perimeters”.
By using the above condition we can write
$ \Rightarrow \dfrac{{AB}}{{DE}} = \dfrac{{BC}}{{EF}} = \dfrac{{AC}}{{DE}} = \dfrac{{{P_1}}}{{{P_2}}}$
Therefore we can write it as
$\dfrac{{AB}}{{DE}} = \dfrac{{{P_1}}}{{{P_2}}}$
By substituting the values in the above condition, we get
$ \Rightarrow \dfrac{{12}}{{DE}} = \dfrac{{30}}{{20}}$
$ \Rightarrow DE = \dfrac{{12 \times 20}}{{30}}$
$ \Rightarrow DE = 8cm$
Hence from this we can say that the length of the corresponding side of the second triangle = $8cm$.
Note: After applying the similar triangle property of perimeter, we have to take the required condition which has values. Avoid unnecessary conditions and calculations.
Complete step-by-step answer:
According to the given data, let us consider
$\Delta ABC$ as the first triangle with the perimeter ${P_1}$.
$\Delta DEF$ as the second triangle with the perimeter ${P_2}$.
Here the triangles $\Delta ABC$ and $\Delta DEF$ are similar triangles.
Given that,
One side of the first triangle is$12cm$, which means $AB = 12cm$($\because $ $\Delta ABC$ is the first triangle).
$
{P_1} = 30cm \\
{P_2} = 20cm \\
$
Since the triangles given are similar triangles.
We know that “Ratio of corresponding sides of similar triangles is equal to the ratio of their perimeters”.
By using the above condition we can write
$ \Rightarrow \dfrac{{AB}}{{DE}} = \dfrac{{BC}}{{EF}} = \dfrac{{AC}}{{DE}} = \dfrac{{{P_1}}}{{{P_2}}}$
Therefore we can write it as
$\dfrac{{AB}}{{DE}} = \dfrac{{{P_1}}}{{{P_2}}}$
By substituting the values in the above condition, we get
$ \Rightarrow \dfrac{{12}}{{DE}} = \dfrac{{30}}{{20}}$
$ \Rightarrow DE = \dfrac{{12 \times 20}}{{30}}$
$ \Rightarrow DE = 8cm$
Hence from this we can say that the length of the corresponding side of the second triangle = $8cm$.
Note: After applying the similar triangle property of perimeter, we have to take the required condition which has values. Avoid unnecessary conditions and calculations.
Recently Updated Pages
Master Class 9 General Knowledge: Engaging Questions & Answers for Success

Master Class 9 Social Science: Engaging Questions & Answers for Success

Master Class 9 English: Engaging Questions & Answers for Success

Master Class 9 Maths: Engaging Questions & Answers for Success

Master Class 9 Science: Engaging Questions & Answers for Success

Class 9 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
What is the median of the first 10 natural numbers class 10 maths CBSE

Which women's tennis player has 24 Grand Slam singles titles?

A Gulab jamun contains sugar syrup up to about 30 of class 10 maths CBSE

Who is the Brand Ambassador of Incredible India?

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

