Answer
424.8k+ views
Hint: In peroxidase anhydrous enzyme, 0.5% Se is present by weight, it means that 0.5 g Se is present in 100 g of enzyme. Minimum molecular formula is defined as the molecular weight divided by the number of atoms of an element present in a molecule.
Complete answer:
As we know, the minimum molecular formula is the molecular weight which is divided by the number of atoms of an element present in a molecule.
$ Minimum\quad molecular\quad weight\quad =\quad \cfrac { Molecular\quad weight }{ No.\quad of\quad atoms\quad of\quad an\quad element }$
In this question, we will be able to find the minimum molecular weight if we consider that in 1 molecule of the peroxidase anhydrous enzyme only 1 Se atom is present. Therefore, the percentage of Se in peroxidase anhydrous enzyme can be found as:
$Percentage \quad of\quad Se\quad =\quad \cfrac { Atomic\quad weight\quad of\quad Se }{ Min.\quad molecular\quad weight\quad (m) } \quad \times \quad 100$
$\implies m\quad =\quad \cfrac { Atomic\quad weight }{ Percentage \quad of\quad Se } \quad \times \quad 100$
Now, given that Atomic weight of Se = 78.4 and 5 of Se = 0.5. Substituting these values in the above equation, we get,
$m\quad =\quad \cfrac { 78.4 }{ 0.5 } \quad \times \quad 100$
$\implies m\quad =\quad 156.8\quad \times \quad 100\quad =\quad 1.568\quad \times \quad { 10 }^{ 4 }\quad g/mol$
Therefore, the minimum molecular weight of Se in peroxidase anhydrous enzymes is $1.586 \times {10}^{4}$.
So, the correct answer is “Option A”.
Note: Don't confuse between the molecular weight and the minimum molecular weight. Molecular weight is the sum of the atomic weights of individual atoms in a molecule. Whereas, minimum molecular weight is the molecular weight divided by the number of atoms of an element present in a molecule.
Complete answer:
As we know, the minimum molecular formula is the molecular weight which is divided by the number of atoms of an element present in a molecule.
$ Minimum\quad molecular\quad weight\quad =\quad \cfrac { Molecular\quad weight }{ No.\quad of\quad atoms\quad of\quad an\quad element }$
In this question, we will be able to find the minimum molecular weight if we consider that in 1 molecule of the peroxidase anhydrous enzyme only 1 Se atom is present. Therefore, the percentage of Se in peroxidase anhydrous enzyme can be found as:
$Percentage \quad of\quad Se\quad =\quad \cfrac { Atomic\quad weight\quad of\quad Se }{ Min.\quad molecular\quad weight\quad (m) } \quad \times \quad 100$
$\implies m\quad =\quad \cfrac { Atomic\quad weight }{ Percentage \quad of\quad Se } \quad \times \quad 100$
Now, given that Atomic weight of Se = 78.4 and 5 of Se = 0.5. Substituting these values in the above equation, we get,
$m\quad =\quad \cfrac { 78.4 }{ 0.5 } \quad \times \quad 100$
$\implies m\quad =\quad 156.8\quad \times \quad 100\quad =\quad 1.568\quad \times \quad { 10 }^{ 4 }\quad g/mol$
Therefore, the minimum molecular weight of Se in peroxidase anhydrous enzymes is $1.586 \times {10}^{4}$.
So, the correct answer is “Option A”.
Note: Don't confuse between the molecular weight and the minimum molecular weight. Molecular weight is the sum of the atomic weights of individual atoms in a molecule. Whereas, minimum molecular weight is the molecular weight divided by the number of atoms of an element present in a molecule.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)