
The oxidation state of nitrogen in:
a.)
b.)
c.)
d.)
Answer
451.2k+ views
2 likes
Hint: Nitrogen compounds exhibit oxidation states ranging from −3 (ammonia or amines) to +5 (nitric acid).
The electronic configuration of nitrogen is:
Nitrogen has 5 outer valence electrons, and the three electrons in 2p orbital are unpaired. Nitrogen can gain three electrons (into 2p orbital) or lose all the 5 valence electrons (from 2s and 2p orbitals) to obtain stable configuration.
Complete answer:
We have to calculate the oxidation states of nitrogen in the given compounds.
The given compounds are
- Hydrazoic acid.
- Ammonia
- Hydroxylamine
- Hydrazine
The oxidation state of nitrogen in is as follows.
There are three nitrogen atoms and one hydrogen atom. So,
3x+1 = 0
x =
The oxidation state of nitrogen in is .
The oxidation state of nitrogen in is as follows.
There is one Nitrogen atom and three hydrogen atoms. So,
x+3(1) = 0
x+3 = 0
x = -3
The oxidation state of nitrogen in is -3.
The oxidation state of nitrogen in is as follows.
The structure of is
We know that there is one hydrogen atom, one oxygen atom and two types of hydrogen atoms.
One type of hydrogen atom (two hydrogens) directly attached to nitrogen and the second type of hydrogen attached to oxygen atom.
x + 3 (+1) – 2 = 0
x = -1
The oxidation state of nitrogen in is -1.
The oxidation state of nitrogen in is as follows.
There are two Nitrogen atoms and four hydrogen atoms.
2x + 4(1) = 0
2x = - 4
x = -2
The oxidation state of nitrogen in is -2.
Note: The various oxidation states of nitrogen are due to the presence of 5 valence electrons. It can donate 5 electrons or it can accept three electrons from other atoms to form stable molecules.
The electronic configuration of nitrogen is:
Nitrogen has 5 outer valence electrons, and the three electrons in 2p orbital are unpaired. Nitrogen can gain three electrons (into 2p orbital) or lose all the 5 valence electrons (from 2s and 2p orbitals) to obtain stable configuration.
Complete answer:
We have to calculate the oxidation states of nitrogen in the given compounds.
The given compounds are
The oxidation state of nitrogen in
There are three nitrogen atoms and one hydrogen atom. So,
3x+1 = 0
x =
The oxidation state of nitrogen in
The oxidation state of nitrogen in
There is one Nitrogen atom and three hydrogen atoms. So,
x+3(1) = 0
x+3 = 0
x = -3
The oxidation state of nitrogen in
The oxidation state of nitrogen in
The structure of

We know that there is one hydrogen atom, one oxygen atom and two types of hydrogen atoms.
One type of hydrogen atom (two hydrogens) directly attached to nitrogen and the second type of hydrogen attached to oxygen atom.
x + 3 (+1) – 2 = 0
x = -1
The oxidation state of nitrogen in
The oxidation state of nitrogen in
There are two Nitrogen atoms and four hydrogen atoms.
2x + 4(1) = 0
2x = - 4
x = -2
The oxidation state of nitrogen in
Note: The various oxidation states of nitrogen are due to the presence of 5 valence electrons. It can donate 5 electrons or it can accept three electrons from other atoms to form stable molecules.
Latest Vedantu courses for you
Grade 11 Science PCM | CBSE | SCHOOL | English
CBSE (2025-26)
School Full course for CBSE students
₹41,848 per year
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Trending doubts
Which one is a true fish A Jellyfish B Starfish C Dogfish class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

How much is 23 kg in pounds class 11 chemistry CBSE

Net gain of ATP in glycolysis a 6 b 2 c 4 d 8 class 11 biology CBSE
