Question

The open chain aliphatic hydrocarbon with molecular formula ${C_9}{H_{16}}$ is :
A.An alkane
B.An alkene
C.An alkyne
D.A cyclic

Answer 1

Hint:In the given question firstly we have to get the number of carbons and the hydrogen which are $9$ and $16$ respectively. Now we can denote the number of the carbons as the $n$ and therefore can get the number of hydrogens in the terms of the $n$ too. That will ultimately give us the answer which is an alkyne, with the chemical configuration of ${C_n}{H_{2n - 2}}$ .

Complete step by step answer:
Here according to the question statement we get that the complete chemical configuration of the compound is therefore:
i.Number of the Carbons : $9$
ii.Number of the hydrogens : $16$
Here the approach to deal with the problem is the observatory one where we have to deduce the relation formula between the given elements so that we can get the information regarding their structural orientation of the atoms and thus the type of the aliphatic hydrocarbon it refers to.
Now the step by step answer to the problem is :
Step 1 : Firstly we have to consider the number of carbons present as the $n$ , so by the comparison we will get that the value of the $n$ is equal to the $9$.
Step 2: Now we have to deduce the value of the hydrogen atoms in the terms of $n$ , to get the direct comparison and the formula too.
So if we get the value of the $2n$ we get that as $18$ which is $2$ less than the number of hydrogens.
So the number of the hydrogens in the terms of $n$ should be denoted as $2n - 2$ .
So that gives us the formula that is ${C_n}{H_{2n - 2}}$ which denotes the general formula of the alkynes.
Therefore the correct option among others would be option C, an alkyne.

Note:
An aliphatic compound or an aliphatic hydrocarbon can be denoted as an organic compound that is containing hydrogen and carbon atoms which are usually linked together in chains that are straight. Sometimes the chains are also in branched trains or in the form of non-aromatic structures.