
The number of constituent particles in a bcc lattice is:
A. 9
B. 8
C. 12
D. 16
Answer
605.4k+ views
Hint: From bcc i.e. body centred cubic (bcc) it means that there is one atom is at the centre of lattice and rest are at the corners.
Complete step-by-step answer:
A crystal lattice is made of a very large number of unit cells and lattice points are the representation of constituent particles. In primitive unit cells, atoms are present at corners only. In a crystal lattice every corner is shared by eight adjacent unit cells. Therefore only 1/8 of an atom, or other constituent particles, belongs to a particular unit cell. There are 8 atoms present in a primitive cubic unit cell on every corner, therefore the total number of atoms in the unit cubic cell = \[8\times \dfrac{1}{8}\] = 1. Now, in bcc (body centred cubic) one atom is present at the centre of the cell and eight atoms are present at each corner.
So, total atoms in a bcc unit cell = 8 corners x \[\dfrac{1}{8}\]atoms per corner + 1centre x 1 atom per unit cell
= \[8\times \dfrac{1}{8}\] + 1
= 2 atoms
But in bcc lattice for constituent particles we count 1 particle at each corner not the 1/8th part.
So, number of constituent particles = 8 at corners + 1 at body centre
= 8+1 = 9 particles
So, the correct answer is “A”.
Note: We should be careful that in this problem we have to calculate the number of constituent particles for the bcc lattice not for the bcc unit cell. If we get confused in both these things then the answer will change.
Complete step-by-step answer:
A crystal lattice is made of a very large number of unit cells and lattice points are the representation of constituent particles. In primitive unit cells, atoms are present at corners only. In a crystal lattice every corner is shared by eight adjacent unit cells. Therefore only 1/8 of an atom, or other constituent particles, belongs to a particular unit cell. There are 8 atoms present in a primitive cubic unit cell on every corner, therefore the total number of atoms in the unit cubic cell = \[8\times \dfrac{1}{8}\] = 1. Now, in bcc (body centred cubic) one atom is present at the centre of the cell and eight atoms are present at each corner.
So, total atoms in a bcc unit cell = 8 corners x \[\dfrac{1}{8}\]atoms per corner + 1centre x 1 atom per unit cell
= \[8\times \dfrac{1}{8}\] + 1
= 2 atoms
But in bcc lattice for constituent particles we count 1 particle at each corner not the 1/8th part.
So, number of constituent particles = 8 at corners + 1 at body centre
= 8+1 = 9 particles
So, the correct answer is “A”.
Note: We should be careful that in this problem we have to calculate the number of constituent particles for the bcc lattice not for the bcc unit cell. If we get confused in both these things then the answer will change.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

