Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store
seo-qna
SearchIcon
banner

The number of carbon atoms present in of acetone (density 1.2gcm3) at 300 K is: 2.0cm3
A.0.083 N
B.0.042 N
C.0.124N
D.0.166 N

Answer
VerifiedVerified
491.1k+ views
like imagedislike image
Hint: Acetone is a ketone and its molecular formula is CH3COCH3. It means that in one molecule of acetone, the number of carbon atoms present are 3. The formula, Density=MassVolume will be used to calculate the mass of the acetone and the mass will be converted to moles.

Complete step by step answer:
Given,
Volume of acetone =2.0cm3
Density of acetone =1.2gcm3
We know
 Density=MassVolume
Therefore, Mass=Density×Volume
Mass of acetone =2×1.2=2.4g
We know that
Number of moles =WeightMolermass
Molar mass of acetone =CH3COCH3
 =12+(1×3)+12+16+12+(1×3)=58g
Number of moles of acetone =2.458=4.14×102
Number of moles of Carbon atoms =3×4.14×102=0.124
So, the number of carbon atoms present in 2.0cm3 of acetone is 0.124.

Therefore, the correct answer is option (C).

Note: Acetone also known as dimethyl ketone. Its chemical formula is CH3COCH3. It is a member of the ketone family. It is a colourless, volatile and flammable liquid and has a fruity and sweetish odour. Acetone may also be present in urine and blood in small quantities. It is used in the nail polish remover. It is also used to make drugs, plastics. Fibres etc. It is a manufactured chemical but also occurs naturally in plants, trees, forest fires. Its melting point is 95.4C and boiling point is 56.53C. Flash point of acetone is 0F.
Latest Vedantu courses for you
Grade 11 Science PCM | CBSE | SCHOOL | English
CBSE (2025-26)
calendar iconAcademic year 2025-26
language iconENGLISH
book iconUnlimited access till final school exam
tick
School Full course for CBSE students
PhysicsPhysics
ChemistryChemistry
MathsMaths
₹41,848 per year
Select and buy