Question

The normality of \[2.3M\] \[{H_2}S{O_4}\] solution is

Answer 1

Hint: Sulphuric acid with the molecular formula \[{H_2}S{O_4}\] is a mineral acid and is made up of the elements sulphur, oxygen, and hydrogen. It is an odourless, colourless, viscous liquid that is miscible in all concentrations of water.

Complete step-by-step answer:
Normality is one of the terms used to describe the concentration of a solution. It is often referred to as the equivalent concentration of a solution. It is abbreviated as \[N\] . It is primarily used to determine the number of reactive species in a solution, as well as during titration reactions and circumstances involving acid-base chemistry.

Normality is defined as the amount of gram or mole equivalents of solute present in one litre of a solution, according to the standard definition. The number of moles of reactive units in a compound is what we mean when we say identical.

Given that, the molarity of the solution is \[2.3M\] .
The following equation can be used to translate molarity to normality.
\[N = \] Molarity \[\left( M \right) \times \] number of equivalents
To determine normality, we must find the number of equivalents.
In nature, sulphuric acid is dibasic. As a result, the number of equivalents is \[2\] .
So, after replacing the values, we will get \[N = 2.3 \times 2 = 4.6N\]

Therefore, the normality of the solution is \[4.6N\] .

Note: Although normality is widely used in precipitation and redox reactions, it has some drawbacks. That is, normality necessitates the existence of a given equivalence factor. It isn't a predetermined value for a specific chemical solution. Depending on the chemical reaction, the value will change dramatically. That is, a single solution may contain multiple normalities for different reactions. It's an undefined unit, so molarity or molality are better alternatives.

Remember the formula to find out the normality using molarity and equivalents.
That is \[N = M \times \] number of equivalents. Keep in mind that the equivalents of \[{H_2}S{O_4}\] is \[2\] .