
The median of 230 observations of the following frequency distribution is 46. Find a and b:
Class 10-20 20-30 30-40 40-50 50-60 60-70 70-80 Frequency 12 30 a 65 b 25 18
| Class | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 |
| Frequency | 12 | 30 | a | 65 | b | 25 | 18 |
Answer
574.8k+ views
Hint: From given information, we will get cumulative frequency. To derive the values of a and b, firstly we have to use median’s equation for given observations. In a given problem, the value of median is given. By using the given median’s value and median formula, we get two equations. On solving these equations, we will get values of a and b.
Complete step-by-step answer:
From given expression, we can add one more row of cumulative frequency as follows:
From given information, we can write
Total observation are = 230
Median = 46
So, median class will be 40-50
Thus, 46 lies between 40-50
Now, the total number of observations will be equal to the cumulative frequency.
\[\begin{array}{l}
150 + a + b = 230\\
a + b = 230 - 150\\
a + b = 80{\rm{ }}...{\rm{(i)}}
\end{array}\]
Now, for the second equation we will use the median formula.
\[median = l + \left( {\dfrac{{\dfrac{n}{2} - cf}}{f}} \right)h\]
But, we have
\[\begin{array}{l}
l = 40\\
cf = 42 + a\\
f = 65\\
\dfrac{n}{2} = 230/2 = 115\\
h = 10
\end{array}\]
Now, we can put all these values in equation
\[46 = 40 + \left( {\dfrac{{115 - \left( {42 + a} \right)}}{{65}}} \right)10\]
On simplification, we get
\[\begin{array}{l}
\Rightarrow 46 - 40 + \left( {\dfrac{{73 - a}}{{65}}} \right)10\\
\Rightarrow 6 \times 65 = 730 - 10a\\
\Rightarrow - 10a = - 340\\
\Rightarrow a = 34
\end{array}\]
Now, put the value of a in equation (i), we get
\[\begin{array}{l}
\Rightarrow b = 80 - a\\
\Rightarrow b = 80 - 34 = 46
\end{array}\]
So, the value of a = 34 and b = 46
Thus the value of a is 34 and b is 46.
Note: Students should know how to calculate cumulative frequency. Students have to take care while calculating cumulative frequency for each observation.
Students make mistakes while using the median formula.
After getting the value of a, one can forget to put the value of in Eq.(i) to get the value of b. Here, we require the value of a as well as b.
Complete step-by-step answer:
From given expression, we can add one more row of cumulative frequency as follows:
| Class | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 |
| Frequency | 12 | 30 | a | 65 | B | 25 | 18 |
| C.F. | 12 | 42 | 42+a | 107+a | 107+a+b | 132+a+b | 150+a+b |
From given information, we can write
Total observation are = 230
Median = 46
So, median class will be 40-50
Thus, 46 lies between 40-50
Now, the total number of observations will be equal to the cumulative frequency.
\[\begin{array}{l}
150 + a + b = 230\\
a + b = 230 - 150\\
a + b = 80{\rm{ }}...{\rm{(i)}}
\end{array}\]
Now, for the second equation we will use the median formula.
\[median = l + \left( {\dfrac{{\dfrac{n}{2} - cf}}{f}} \right)h\]
But, we have
\[\begin{array}{l}
l = 40\\
cf = 42 + a\\
f = 65\\
\dfrac{n}{2} = 230/2 = 115\\
h = 10
\end{array}\]
Now, we can put all these values in equation
\[46 = 40 + \left( {\dfrac{{115 - \left( {42 + a} \right)}}{{65}}} \right)10\]
On simplification, we get
\[\begin{array}{l}
\Rightarrow 46 - 40 + \left( {\dfrac{{73 - a}}{{65}}} \right)10\\
\Rightarrow 6 \times 65 = 730 - 10a\\
\Rightarrow - 10a = - 340\\
\Rightarrow a = 34
\end{array}\]
Now, put the value of a in equation (i), we get
\[\begin{array}{l}
\Rightarrow b = 80 - a\\
\Rightarrow b = 80 - 34 = 46
\end{array}\]
So, the value of a = 34 and b = 46
Thus the value of a is 34 and b is 46.
Note: Students should know how to calculate cumulative frequency. Students have to take care while calculating cumulative frequency for each observation.
Students make mistakes while using the median formula.
After getting the value of a, one can forget to put the value of in Eq.(i) to get the value of b. Here, we require the value of a as well as b.
Recently Updated Pages
You are the Editor of your school magazine Draft a class 10 english CBSE

A motor boat whose speed is 20 kmhr in still water-class-10-maths-CBSE

Why Gandhiji decided to withdraw the Non Cooperation class 10 social studies CBSE

A Gulab jamun contains sugar syrup up to about 30 of class 10 maths CBSE

Five things I will do to build a great India class 10 english CBSE

Find the area of the segment AYB shown in figure if class 10 maths CBSE

Trending doubts
Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Which of the following does not have a fundamental class 10 physics CBSE

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

