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The mean distance of mars from the sun is 1.524 times that of the earth from the sun. Find the number of years required for mars to make one revolution about the sun.
A. 1.883
B. 2
C. 3.766
D. 4

Answer
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Hint: Assume that both mars and earth revolve around the sun circular paths with sun at the centre. Then use the Kepler’s law, which gives the relation between the time period of revolution of the planet around the sun and the radius of the path.

Formula used:
T2=kr3

Complete answer:
It is given that the mean distance between mars and sun is 1.524 times the distance between the earth and the sun.
Let the mean distance between the mars and the sun be r1 and the mean distance between the earth and the sun be r2.
Let us assume that the mars and the earth are moving in circular paths of radius r1 and r2 respectively.
r1r2=1.524
According to Kepler's law, the square of the time period of an object moving in a circular path is directly proportional to the cube of the radius of the circular path.
i.e. T2r3.
T2=kr3, where k is a proportionality constant.
Let the time periods of revolution the mars and the earth be T1 and T2 respectively.
Therefore,
T12=kr13 ….. (i).
And
T22=kr23 …… (ii).
Divide (i) and (ii).
T12T22=kr13kr23
T12T22=(r1r2)3… (iii).
The time period of earth is 1 year.
Hence, T2 = 1yr.
Substitute the values of T2 and r1r2 in equation (iii).
T12(1)2=(1.524)3
T1=(1.524)32=1.88years.

So, the correct answer is “Option A”.

Note:
Note that we have assumed that the mars and the earth revolve around the sun in circular paths.
In reality, they revolve in elliptical paths with the sun positioned at one of the foci of the elliptical paths. Therefore, the distance between the sun and the planets is not constant.
Hence, we consider the mean distance between the sun and the planets.
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