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The Maclaurin expansion of sinx is given by Sinx=x1!x33!+x55!x77!+......., where x is in radians. Use the series to compute the value of sin25 with an accuracy of 0.001.

Answer
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Hint: We start solving the problem by recalling the conversion of degrees to the radians. We then convert the given 25 to the radians using this conversion. We then substitute the obtained value of radians in the place of x in the Maclaurin expansion. We then make the necessary calculations and neglect the values that were less than 0.001 to get the required result.

Complete step by step answer:
According to the problem, we have given Maclaurin expansion of sinx as Sinx=x1!x33!+x55!x77!+......., where x is in radians. We need to compute the value of sin25 with an accuracy of 0.001 using this series.
Let us first convert 25 into the radians. We know that 1 is equal to π180 radians or 0.0174 radians. Using this we get 25=25×0.0174.
25=0.435 radians. Now, let us use this in the expansion of sinx to get the value of sin25.
We know that n!=n×(n1)×(n2)×(n3)×........
So, we have Sin25=0.4351(0.435)33×2×1+(0.435)55×4×3×2×1(0.435)77×6×5×4×3×2×1+........
Sin25=0.4350.08236+0.01561200.00295040+........
Sin25=0.4350.014+0.00013, we neglected next terms as we can see that the values are less than 0.001.
Sin25=0.421.
So, we have found the approximate value of sin25 as 0.421.

∴ The value of sin25 computed by using Maclaurin expansion is 0.421.

Note: The value we got by solving using the Maclaurin method is an approximate value not the absolute value. To get the absolute value, we need to check the tables of the sine or we can check from the graph. The value we obtained will be as near as possible to the absolute value. We can also find the value of sin25 from the sin300 by using sin6θ to get the absolute value.
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