
The line segment joining (2, -3) and (5, 6) is divided by x-axis in the ratio:
a. 2:1
b. 3:1
c. 1:2
d. 1:3
Answer
513k+ views
Hint: We know that if any line segment joining to points let say A and B are divided by any other point C in a certain amount of ratio. Then the coordinates of C are given by the formula namely section formula, which is, \[{\text{(x,y) = (}}\dfrac{{{\text{mc + na}}}}{{{\text{m + n}}}}{\text{,}}\dfrac{{{\text{md + nb}}}}{{{\text{m + n}}}}{\text{)}}\], where (x,y) is coordinates of C, (a,b) and (c,d) are the coordinates of A and B.
Using section formula, on simplifying we’ll get the equation to simplify for the ratio in which the x-axis divides the line segment, so the coordinate of any point on the x-axis is (a,0). Using this we can find the required ratio.
Complete step by step Answer:
Given: x-axis divides the line segment joining (2, -3) and (5, 6)
Let the point where this line segment divides the x-axis be, (a, 0), and also let the x-axis divide this line segment in the ratio m: n as all the ordinate of the points in the x-axis is zero.
Now we know, if a line joining \[{\text{(a,b)}}\]and \[{\text{(c,d)}}\] gets divided by a point \[{\text{(x,y)}}\] in the ratio \[{\text{m:n}}\],
Then using section formula we can find the coordinates(x,y)
i.e. \[{\text{(x,y) = (}}\dfrac{{{\text{mc + na}}}}{{{\text{m + n}}}}{\text{,}}\dfrac{{{\text{md + nb}}}}{{{\text{m + n}}}}{\text{)}}\]
now according to the given data, we have the points as\[{\text{(a,b) = (2, - 3)}}\] , and \[{\text{(c,d) = (5,6)}}\]
So on substituting the above values we get,
\[{\text{(a,0) = (}}\dfrac{{{\text{m}} \times {\text{5 + n}} \times {\text{2}}}}{{{\text{m + n}}}}{\text{,}}\dfrac{{{\text{m6 + n( - 3)}}}}{{{\text{m + n}}}}{\text{)}}\]
Now on equating the y components, we get,
\[\dfrac{{{\text{m(6) + n( - 3)}}}}{{{\text{m + n}}}} = 0\]
Multiplying both sides by (m+n)
\[ \Rightarrow {\text{6m - 3n = 0}}\]
\[ \Rightarrow {\text{6m = 3n}}\]
Dividing both sides by 3
\[ \Rightarrow 2{\text{m = n}}\]
Now to get the value of ratio dividing both sides by n
\[\therefore \dfrac{{\text{m}}}{{\text{n}}}{\text{ = }}\dfrac{{\text{1}}}{{\text{2}}}\]
Hence the correct option is C.
Note: We use section formula to find the coordinates of a point which divides the line joining two points in a ratio, internally or externally. If the value of the ratio is negative then the point is external, whereas if the value of the ratio is positive then the point is internal.
Using section formula, on simplifying we’ll get the equation to simplify for the ratio in which the x-axis divides the line segment, so the coordinate of any point on the x-axis is (a,0). Using this we can find the required ratio.
Complete step by step Answer:
Given: x-axis divides the line segment joining (2, -3) and (5, 6)
Let the point where this line segment divides the x-axis be, (a, 0), and also let the x-axis divide this line segment in the ratio m: n as all the ordinate of the points in the x-axis is zero.
Now we know, if a line joining \[{\text{(a,b)}}\]and \[{\text{(c,d)}}\] gets divided by a point \[{\text{(x,y)}}\] in the ratio \[{\text{m:n}}\],
Then using section formula we can find the coordinates(x,y)
i.e. \[{\text{(x,y) = (}}\dfrac{{{\text{mc + na}}}}{{{\text{m + n}}}}{\text{,}}\dfrac{{{\text{md + nb}}}}{{{\text{m + n}}}}{\text{)}}\]
now according to the given data, we have the points as\[{\text{(a,b) = (2, - 3)}}\] , and \[{\text{(c,d) = (5,6)}}\]
So on substituting the above values we get,
\[{\text{(a,0) = (}}\dfrac{{{\text{m}} \times {\text{5 + n}} \times {\text{2}}}}{{{\text{m + n}}}}{\text{,}}\dfrac{{{\text{m6 + n( - 3)}}}}{{{\text{m + n}}}}{\text{)}}\]
Now on equating the y components, we get,
\[\dfrac{{{\text{m(6) + n( - 3)}}}}{{{\text{m + n}}}} = 0\]
Multiplying both sides by (m+n)
\[ \Rightarrow {\text{6m - 3n = 0}}\]
\[ \Rightarrow {\text{6m = 3n}}\]
Dividing both sides by 3
\[ \Rightarrow 2{\text{m = n}}\]
Now to get the value of ratio dividing both sides by n
\[\therefore \dfrac{{\text{m}}}{{\text{n}}}{\text{ = }}\dfrac{{\text{1}}}{{\text{2}}}\]
Hence the correct option is C.
Note: We use section formula to find the coordinates of a point which divides the line joining two points in a ratio, internally or externally. If the value of the ratio is negative then the point is external, whereas if the value of the ratio is positive then the point is internal.
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
Which one is a true fish A Jellyfish B Starfish C Dogfish class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Net gain of ATP in glycolysis a 6 b 2 c 4 d 8 class 11 biology CBSE
