The line segment joining (2, -3) and (5, 6) is divided by x-axis in the ratio:
a. 2:1
b. 3:1
c. 1:2
d. 1:3
Answer
651k+ views
Hint: We know that if any line segment joining to points let say A and B are divided by any other point C in a certain amount of ratio. Then the coordinates of C are given by the formula namely section formula, which is, \[{\text{(x,y) = (}}\dfrac{{{\text{mc + na}}}}{{{\text{m + n}}}}{\text{,}}\dfrac{{{\text{md + nb}}}}{{{\text{m + n}}}}{\text{)}}\], where (x,y) is coordinates of C, (a,b) and (c,d) are the coordinates of A and B.
Using section formula, on simplifying we’ll get the equation to simplify for the ratio in which the x-axis divides the line segment, so the coordinate of any point on the x-axis is (a,0). Using this we can find the required ratio.
Complete step by step Answer:
Given: x-axis divides the line segment joining (2, -3) and (5, 6)
Let the point where this line segment divides the x-axis be, (a, 0), and also let the x-axis divide this line segment in the ratio m: n as all the ordinate of the points in the x-axis is zero.
Now we know, if a line joining \[{\text{(a,b)}}\]and \[{\text{(c,d)}}\] gets divided by a point \[{\text{(x,y)}}\] in the ratio \[{\text{m:n}}\],
Then using section formula we can find the coordinates(x,y)
i.e. \[{\text{(x,y) = (}}\dfrac{{{\text{mc + na}}}}{{{\text{m + n}}}}{\text{,}}\dfrac{{{\text{md + nb}}}}{{{\text{m + n}}}}{\text{)}}\]
now according to the given data, we have the points as\[{\text{(a,b) = (2, - 3)}}\] , and \[{\text{(c,d) = (5,6)}}\]
So on substituting the above values we get,
\[{\text{(a,0) = (}}\dfrac{{{\text{m}} \times {\text{5 + n}} \times {\text{2}}}}{{{\text{m + n}}}}{\text{,}}\dfrac{{{\text{m6 + n( - 3)}}}}{{{\text{m + n}}}}{\text{)}}\]
Now on equating the y components, we get,
\[\dfrac{{{\text{m(6) + n( - 3)}}}}{{{\text{m + n}}}} = 0\]
Multiplying both sides by (m+n)
\[ \Rightarrow {\text{6m - 3n = 0}}\]
\[ \Rightarrow {\text{6m = 3n}}\]
Dividing both sides by 3
\[ \Rightarrow 2{\text{m = n}}\]
Now to get the value of ratio dividing both sides by n
\[\therefore \dfrac{{\text{m}}}{{\text{n}}}{\text{ = }}\dfrac{{\text{1}}}{{\text{2}}}\]
Hence the correct option is C.
Note: We use section formula to find the coordinates of a point which divides the line joining two points in a ratio, internally or externally. If the value of the ratio is negative then the point is external, whereas if the value of the ratio is positive then the point is internal.
Using section formula, on simplifying we’ll get the equation to simplify for the ratio in which the x-axis divides the line segment, so the coordinate of any point on the x-axis is (a,0). Using this we can find the required ratio.
Complete step by step Answer:
Given: x-axis divides the line segment joining (2, -3) and (5, 6)
Let the point where this line segment divides the x-axis be, (a, 0), and also let the x-axis divide this line segment in the ratio m: n as all the ordinate of the points in the x-axis is zero.
Now we know, if a line joining \[{\text{(a,b)}}\]and \[{\text{(c,d)}}\] gets divided by a point \[{\text{(x,y)}}\] in the ratio \[{\text{m:n}}\],
Then using section formula we can find the coordinates(x,y)
i.e. \[{\text{(x,y) = (}}\dfrac{{{\text{mc + na}}}}{{{\text{m + n}}}}{\text{,}}\dfrac{{{\text{md + nb}}}}{{{\text{m + n}}}}{\text{)}}\]
now according to the given data, we have the points as\[{\text{(a,b) = (2, - 3)}}\] , and \[{\text{(c,d) = (5,6)}}\]
So on substituting the above values we get,
\[{\text{(a,0) = (}}\dfrac{{{\text{m}} \times {\text{5 + n}} \times {\text{2}}}}{{{\text{m + n}}}}{\text{,}}\dfrac{{{\text{m6 + n( - 3)}}}}{{{\text{m + n}}}}{\text{)}}\]
Now on equating the y components, we get,
\[\dfrac{{{\text{m(6) + n( - 3)}}}}{{{\text{m + n}}}} = 0\]
Multiplying both sides by (m+n)
\[ \Rightarrow {\text{6m - 3n = 0}}\]
\[ \Rightarrow {\text{6m = 3n}}\]
Dividing both sides by 3
\[ \Rightarrow 2{\text{m = n}}\]
Now to get the value of ratio dividing both sides by n
\[\therefore \dfrac{{\text{m}}}{{\text{n}}}{\text{ = }}\dfrac{{\text{1}}}{{\text{2}}}\]
Hence the correct option is C.
Note: We use section formula to find the coordinates of a point which divides the line joining two points in a ratio, internally or externally. If the value of the ratio is negative then the point is external, whereas if the value of the ratio is positive then the point is internal.
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