Question

The length, breadth and height of a cuboid are 6 cm, 4 cm and 5 cm respectively. Find the total surface area of the cuboid.

Answer 1

Hint: In the above given question, we are asked to calculate the total surface area of the cuboid, which is equal to the sum of the areas of the six rectangular faces of the cuboid which comes out to be$2(lb + bh + hl)$.

Complete step-by-step answer:
We have the given dimensions of the cuboid as:

Length of the cuboid\[l = 6cm\]

Breadth of the cuboid\[b = 4cm\]

Height of the cuboid$h = 5cm$

We know that the total surface area of the cuboid$ = 2(lb + bh + hl)$.

By substituting the values of length, breadth and height of the cuboid in the above given formula, we get,

$ = 2(6 \times 4 + 4 \times 5 + 6 \times 5)c{m^2}$

$ = 2(24 + 20 + 30)c{m^2}$

$ = 2(74)c{m^2}$

$ = 148c{m^2}$

Hence, the total surface area of the cuboid$ = 148c{m^2}$.

Note: When we face such a type of problem, the key point is to have a good knowledge of the surface areas of the solids. The given values can be substituted in the formula of the total surface area, which on further evaluation leads to the required solution.