Question

The length and breadth of three rectangles are as given below:
a) \[9m\] and \[6m\] b) \[17m\] and \[3m\] c) \[4m\] and \[14m\]
Which one has the largest area and which one has the smallest?

Answer 1

Hint: Start by finding the areas of all three rectangles and then comparing the values.
Here we have been given with the lengths and breadths of three rectangles and we are supposed to find out which rectangle has the largest area and which one has the smallest area.

Complete Step-by-Step Solution:-
So, for that, the first step is to find out the area of these three rectangles.
How do we find the area of a rectangle?
The formula to find the area of rectangle is:
Area = length $ \times $ breadth
A). So, for the first option we have length to be equal to \[9m\] and breadth to be equal to \[6m\]
Therefore,
Area =$9m \times 6m$
                 =$54{m^2}$
B). So, for the first option we have length to be equal to \[17m\] and breadth to be equal to \[3m\]
Therefore,
Area =$17m \times 3m$
          = $51{m^2}$.
C). So, for the first option we have length to be equal to \[4m\] and breadth to be equal to \[14m\]
Therefore,
Area = $4m \times 14m$
          =$56{m^2}$
Therefore,
Largest area=$56{m^2}$
Smallest area=$51{m^2}$

Note: Make sure to write the units.
We have all the three areas now, if we compare these three values we can see that the area in the first case is $54{m^2}$, in the second case it is $51{m^2}$, and in the third case it is $56{m^2}$ by comparing we get to know the smallest and largest area.