
The largest number of the three consecutive numbers is $x + 1$then, the smallest number is
A) $x + 2$
B) $x + 1$
C) $x$
D) $x - 1$\[\]
Answer
591k+ views
Hint: In simple words, consecutive numbers are the numbers that follow each other continuously in order from the smallest to the largest. In these types of problems, we use the concept of consecutive numbers and adding 1 to number; we can get the next number, subtracting 1 from the number we can per preceding number as it is not mentioning the type of number, so we will consider it as the natural number. We will use the concept of consecutive numbers. There is a difference of 1 between two consecutive numbers. For example, $1,2,3{\text{ and 10,11,12}}$ are the consecutive numbers.
Complete step-by -step solution:
The largest of consecutive numbers is \[\left( {x + 1} \right)\].
We know that the consecutive numbers differ by \[1\].
So the consecutive number before \[\left( {x + 1} \right)\] is \[\left( {x + 1} \right) - 1\; = x\].
And the consecutive number before \[x\] is\[x - 1\].
The first number of the three consecutive numbers will be\[\left( {x - 1} \right)\].
We know that,
\[\left( {x - 1} \right) < x < \left( {x + 1} \right)\].
As the consecutive numbers follow the order from the smallest to the largest number.
So the smallest of all consecutive numbers are\[x - 1\].
Hence, the largest number of the three consecutive numbers is $x + 1$then, the smallest number is \[x - 1\]
Hence, Option D is the correct answer.
Note:If it is an Even or Odd number, we need to make a difference of 2 between two consecutive Even or Odd numbers depending on the mentioned condition.
Complete step-by -step solution:
The largest of consecutive numbers is \[\left( {x + 1} \right)\].
We know that the consecutive numbers differ by \[1\].
So the consecutive number before \[\left( {x + 1} \right)\] is \[\left( {x + 1} \right) - 1\; = x\].
And the consecutive number before \[x\] is\[x - 1\].
The first number of the three consecutive numbers will be\[\left( {x - 1} \right)\].
We know that,
\[\left( {x - 1} \right) < x < \left( {x + 1} \right)\].
As the consecutive numbers follow the order from the smallest to the largest number.
So the smallest of all consecutive numbers are\[x - 1\].
Hence, the largest number of the three consecutive numbers is $x + 1$then, the smallest number is \[x - 1\]
Hence, Option D is the correct answer.
Note:If it is an Even or Odd number, we need to make a difference of 2 between two consecutive Even or Odd numbers depending on the mentioned condition.
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