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The IUPAC name of the given compound is:
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(A) 3-methyl cyclohexene
(B) 1-methyl cyclohex-2-ene
(C) 6-methyl cyclohexene
(D) 1-methyl cyclohex-5-ene


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Last updated date: 13th Jun 2024
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Answer
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Hint: If a carbon-carbon double bond is present in the compound, then the functional group is called alkene and we use –ene suffix to show its presence. The alkene carbons should be given lower numbers in the process of numbering the chain.

Complete step by step solution:
We will try to give IUPAC names to the given compound.
- We can see that a carbon-carbon double bond is present in the compound. So, the alkene functional group is present in the compound. We know that –ene is the suffix used to describe the presence of alkene functional groups.
- We can see that there is a cyclic ring present which is made up of six carbons. So, we can call this ring a cyclohexane ring.
- Methyl group is there as a substituent on the cyclohexane ring.
- So, we will take cyclohexane rings as a parent chain of carbons.
- In numbering of the carbons, we should give numbering in a way that both $s{p^2}$ hybridized carbons get the priority. Then the carbon atom bearing methyl group should be considered to have the lowest number.
- Thus, we can give numbers to the carbon atoms in a given manner.

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So, we can say that methyl group is present on carbon number 3. We can also say that the alkene functional group is present on carbon number 1. So, the IUPAC name of this compound will be 3-methyl cyclohexene

Therefore, the correct answer of the question is (A).

Note: If more than one similar substituent groups are present, then we can use prefixes like di-, tri-, tetra- etc. If more than one substituent groups are present, then we need to write them in an alphabetical manner in IUPAC name of the compound.