Question

The IUPAC name of $ \left[ Fe{{\left( {{H}_{2}}O \right)}_{5}}\left( NO \right) \right]S{{O}_{4}} $ pentaaqua aquanitrosylium iron $ \left( I \right) $ sulphate.
(A) True.
(B) False.

Answer 1

Hint: We know that while answering such questions the student should follow the steps for IUPAC nomenclature for complex compounds. IUPAC full form is International Union of Pure and Applied Chemistry; it is a world authority for giving chemistry based terminologies, units, nomenclatures, etc.

Complete step by step solution:
Now, we are given the complex $ \left[ Fe{{\left( {{H}_{2}}O \right)}_{5}}\left( NO \right) \right]S{{O}_{4}} $ . As mentioned, the complex is neutral. So, we can calculate the oxidation state of Fe in the ring. The ligands present in the complex are aqua, nitrosyl, and sulphate ion.
First, let’s go through the steps which are used for naming the complex compounds.
When naming, Ligand is to be named first.
While writing the names of ligand it should be in the following order: neutral, negative, positive.
If multiple ligands have the same charge then they should be named in alphabetical order. If a ligand is having multiple occurrences (monodentate) in that case we use the prefixes like – di, tri, tetra, penta, hexa respectively.
For polydentate ligands we use –bis-, tris-, tetrakis-, etc. Anions ends with –ido. Like anion ending with e becomes ato example, sulphate becomes sulphato and e becomes ‘ido’, example, cyanide becomes cyanide.
Neutral ligands are given their usual names.
After that write the name of the central atom/ion. If the complex is an anion then it will end with –ate and its Latin name is to be used except in case of mercury. If it is required to specify the oxidation state(in case of atoms with multiple oxidation states) us Roman numerals.
End with “cation” or “anion” as separate (if applicable).
Now start with naming the complex compound:
The IUPAC name of $ \left[ Fe{{\left( {{H}_{2}}O \right)}_{5}}\left( NO \right) \right]S{{O}_{4}} $ ​ is penta aquanitrosylium iron $ \left( I \right)~ $ sulphate.
Therefore, the correct answer is option A.

Note:
Remember that the behaviour of nitric oxide can be determined by calculating the oxidation state. The electron transfer can be observed, but the whole complex is neutral with the charge zero. So, it will help to observe the behaviour in the coordination compound.