Answer
Verified
372k+ views
Hint: Extent of hydrogen bonding is more in case of hydrogen peroxide as compared to water. Also the polarizability of hydrogen peroxide is more than water due to greater dipole moment. The compounds having stronger intermolecular force of attraction have greater value of melting and boiling point.
Complete step by step answer:
Hydrogen bonding is an electrostatic attractive force between covalently, bonded hydrogen atoms of one molecule and an electronegative atom like fluorine, oxygen and nitrogen. It is not formed in ionic compounds and forms in polar covalent compounds. It's a weak bond but stronger than van der waal force. For this, hydrogen should be bonded with high electronegative element like fluorine, oxygen and nitrogen. Boiling points and melting points of compounds increase due to intermolecular hydrogen bonding. Sudden increase in boiling point of ammonia, water and HF is due to hydrogen bonding. Intramolecular hydrogen bonding gives rise to ring formation, so the force of attraction among these molecules are van der waal force and so melting and boiling point are low for these compounds.
\[{{\text{H}}_2}{{\text{O}}_2}\] has boiling point of about \[{150^o}{\text{C}}\] and boiling point of water is \[{100^o}{\text{C}}\] . This difference in their boiling point can be attributed by variation in strength of intermolecular forces. As hydrogen peroxide has greater polarizability, stronger London dispersion force, and greater dipole moment as compared to water. Hydrogen peroxide exhibits hydrogen bonding more as compared to water which greatly impacts on its boiling point. The bottom line is that all three types of intermolecular forces are stronger for hydrogen peroxide than water which accounts for the greater boiling point of hydrogen peroxide than water.
Thus, the correct option is A.
Note:
Dipole moment of hydrogen peroxide is \[2.26{\text{Debye}}\] and on the other hand, dipole moment of water is \[1.86{\text{Debye}}\] . Greater dipole moments correspond to the greater polarizability of the compound or molecule.
Complete step by step answer:
Hydrogen bonding is an electrostatic attractive force between covalently, bonded hydrogen atoms of one molecule and an electronegative atom like fluorine, oxygen and nitrogen. It is not formed in ionic compounds and forms in polar covalent compounds. It's a weak bond but stronger than van der waal force. For this, hydrogen should be bonded with high electronegative element like fluorine, oxygen and nitrogen. Boiling points and melting points of compounds increase due to intermolecular hydrogen bonding. Sudden increase in boiling point of ammonia, water and HF is due to hydrogen bonding. Intramolecular hydrogen bonding gives rise to ring formation, so the force of attraction among these molecules are van der waal force and so melting and boiling point are low for these compounds.
\[{{\text{H}}_2}{{\text{O}}_2}\] has boiling point of about \[{150^o}{\text{C}}\] and boiling point of water is \[{100^o}{\text{C}}\] . This difference in their boiling point can be attributed by variation in strength of intermolecular forces. As hydrogen peroxide has greater polarizability, stronger London dispersion force, and greater dipole moment as compared to water. Hydrogen peroxide exhibits hydrogen bonding more as compared to water which greatly impacts on its boiling point. The bottom line is that all three types of intermolecular forces are stronger for hydrogen peroxide than water which accounts for the greater boiling point of hydrogen peroxide than water.
Thus, the correct option is A.
Note:
Dipole moment of hydrogen peroxide is \[2.26{\text{Debye}}\] and on the other hand, dipole moment of water is \[1.86{\text{Debye}}\] . Greater dipole moments correspond to the greater polarizability of the compound or molecule.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred
What is the stopping potential when the metal with class 12 physics JEE_Main
The momentum of a photon is 2 times 10 16gm cmsec Its class 12 physics JEE_Main
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
What is BLO What is the full form of BLO class 8 social science CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Fill the blanks with proper collective nouns 1 A of class 10 english CBSE
What organs are located on the left side of your body class 11 biology CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
What is the z value for a 90 95 and 99 percent confidence class 11 maths CBSE