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Hint: Find the equation of acceleration due to gravity and gravitational field intensity. Acceleration due to gravity is g and equal to $G\dfrac{{{m}_{1}}}{{{r}^{2}}}$. The intensity of gravitational field at a point is given by equation $\overrightarrow{E}=\dfrac{\overrightarrow{F}}{m}$, Where $\overrightarrow{F}=m\overrightarrow{g}$.
Complete step by step answer:
Acceleration due to gravity-
The gravitational force between two masses is proportional to the product of mass and is inversely proportional to square of the distance apart,
$\begin{align}
& F\propto \dfrac{{{m}_{1}}{{m}_{2}}}{{{r}^{2}}} \\
& F=G\dfrac{{{m}_{1}}{{m}_{2}}}{{{r}^{2}}} \\
\end{align}$
The term $G\dfrac{{{m}_{1}}}{{{r}^{2}}}$is called acceleration due to gravity and is denoted by the letter g.
Gravitational field –
When a body is placed in a gravitational field, this field exerts a force on it. And the direction and the intensity of the field are defined in terms of the force it exerts on a body planed in it.
The intensity of gravitational field at a point is given by equation-
$\overrightarrow{E}=\dfrac{\overrightarrow{F}}{m}$
Where, $\overrightarrow{F}$= force exerted by the field on a body of mass m placed in a gravitational field.
If a mass m is placed close to the surface of the earth, the force on it is $\overrightarrow{F}=m\overrightarrow{g}$
$\begin{align}
& \overrightarrow{E}=\dfrac{\overrightarrow{F}}{m} \\
& \overrightarrow{E}=\dfrac{m\overrightarrow{g}}{m}=\overrightarrow{g} \\
\end{align}$
Thus the intensity of the gravitational field near the surface of the earth is equal to the acceleration due to gravity.
Note: When a body creates a gravitational field in a space around it. The field has its own existence and has energy and momentum. This field has a definite direction at each point of the space.
Acceleration due to gravity and intensity of the gravitational field are two separate physical quantities having equal magnitude and directions.
Complete step by step answer:
Acceleration due to gravity-
The gravitational force between two masses is proportional to the product of mass and is inversely proportional to square of the distance apart,
$\begin{align}
& F\propto \dfrac{{{m}_{1}}{{m}_{2}}}{{{r}^{2}}} \\
& F=G\dfrac{{{m}_{1}}{{m}_{2}}}{{{r}^{2}}} \\
\end{align}$
The term $G\dfrac{{{m}_{1}}}{{{r}^{2}}}$is called acceleration due to gravity and is denoted by the letter g.
Gravitational field –
When a body is placed in a gravitational field, this field exerts a force on it. And the direction and the intensity of the field are defined in terms of the force it exerts on a body planed in it.
The intensity of gravitational field at a point is given by equation-
$\overrightarrow{E}=\dfrac{\overrightarrow{F}}{m}$
Where, $\overrightarrow{F}$= force exerted by the field on a body of mass m placed in a gravitational field.
If a mass m is placed close to the surface of the earth, the force on it is $\overrightarrow{F}=m\overrightarrow{g}$
$\begin{align}
& \overrightarrow{E}=\dfrac{\overrightarrow{F}}{m} \\
& \overrightarrow{E}=\dfrac{m\overrightarrow{g}}{m}=\overrightarrow{g} \\
\end{align}$
Thus the intensity of the gravitational field near the surface of the earth is equal to the acceleration due to gravity.
Note: When a body creates a gravitational field in a space around it. The field has its own existence and has energy and momentum. This field has a definite direction at each point of the space.
Acceleration due to gravity and intensity of the gravitational field are two separate physical quantities having equal magnitude and directions.
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