
The geometry of and are:
a.) Both square planar
b.) Tetrahedral and square planar
c.) Both tetrahedral
d.) Square planar and tetrahedral
Answer
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Hint: To solve this question, we must focus on the connection between coordination number and geometry of a coordination complex. It is important to note that every geometry has a specific coordination number associated with it, but every complex molecule with the specific coordination number can have a choice of several possible geometries.
Complete step by step answer:
Let us take a look at the different geometries associated with coordination numbers.
Complexes having coordination number 2 always have a linear geometry.
Coordination complex molecules having coordination number 3 either have a trigonal planar geometry or a trigonal pyramidal geometry. If there are certain distortions, these molecules become T-shaped.
For coordination number 4, two different geometries are possible. A molecule may have a tetrahedral geometry or a square planar one.
We will now find the coordination number of the molecules assigned to us:
:
We find that the oxidation number of Nickel here is 0 since CO has 0 charge as well.
If we write the electronic configuration,
Ground state Ni=
Upon excitation,
We can place 8 electrons in 3d orbital and 2 electrons in 4s.
But we know that CO is a strong ligand, hence electrons are paired up in 3d orbital and 4s remains empty giving the molecule hybridization and a tetrahedral geometry.
:
The oxidation number of Ni here is +2 since is neutral and chlorine is -1.
We will place 8 electrons in 3d orbital whereas 4s and 4p remains empty.
Without even pairing up, the 4 subshell remains empty giving it a hybridization and a tetrahedral geometry.
Hence, the correct answer is Option (C) Both Tetrahedral.
Note:
The coordination compounds have distinct geometric structures. Only on altering the relative position of atoms we find different geometries in space with the same molecular formula.
Complete step by step answer:
Let us take a look at the different geometries associated with coordination numbers.
Complexes having coordination number 2 always have a linear geometry.
Coordination complex molecules having coordination number 3 either have a trigonal planar geometry or a trigonal pyramidal geometry. If there are certain distortions, these molecules become T-shaped.
For coordination number 4, two different geometries are possible. A molecule may have a tetrahedral geometry or a square planar one.
We will now find the coordination number of the molecules assigned to us:
We find that the oxidation number of Nickel here is 0 since CO has 0 charge as well.
If we write the electronic configuration,
Ground state Ni=
Upon excitation,
We can place 8 electrons in 3d orbital and 2 electrons in 4s.
But we know that CO is a strong ligand, hence electrons are paired up in 3d orbital and 4s remains empty giving the molecule
The oxidation number of Ni here is +2 since
We will place 8 electrons in 3d orbital whereas 4s and 4p remains empty.
Without even pairing up, the 4 subshell remains empty giving it a
Hence, the correct answer is Option (C) Both Tetrahedral.
Note:
The coordination compounds have distinct geometric structures. Only on altering the relative position of atoms we find different geometries in space with the same molecular formula.
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