
The gas equation for a real gas is: P(V-b) = RT. Here the parameter ‘b’ is Van der Waals constant. The graph of pressure against temperature (isochore) will give a straight line of slope:
[A] Zero
[B] $\dfrac{R}{\left( V-b \right)}$
[C] $\dfrac{R}{P}$
[D] Negative
Answer
587.1k+ views
HINT: Gas equation gives us a relation between pressure temperature and volume for real gases. Real gases do not follow the gas equation of ideal gases. To solve this compare the given equation with the equation of a straight line.
COMPLETE STEP BY STEP SOLUTION: The ideal gas law equation is an equation of state variables of a hypothetical ideal gas. We know that the ideal gas equation is – PV = nRT where, P is the pressure, V is the volume of the gas, n is the number of moles, R is the universal gas constant which has a fixed value and T is the temperature.
However, for a real gas we make some changes to this ideal gas equation. We add a pressure term and subtract a volume term.
However, excluding the extra pressure term it is given as- P (V-b) = RT.
We know that the equation of a straight line is- y = mx + c
Where, m is the slope and c is the intercept and x and y depicts the two axes.
Rearranging equation P (V-b) = RT we can write that –
\[P=\dfrac{R}{(V-b)}T\]
Therefore, we have the relation between pressure and temperature for an isochoric curve.
Now if we compare this equation with the straight line equation we will see that the slope m is $\dfrac{R}{(V-b)}$ .
Hence, we can see from the above discussion that the slope of pressure against the temperature graph will be $\dfrac{R}{(V-b)}$.
Therefore, the correct answer is option [B] $\dfrac{R}{\left( V-b \right)}$.
NOTE: The ideal gas law equation is an equation of state variables of a hypothetical ideal gas. It has many limitations but still used for approximation of behaviour of a gas under certain conditions. It is a combination of Boyle’s law, Avogadro’s law, Charles’s law and Gay-Lussac’s law. Real gases do not obey the ideal gas law and therefore a gas equation for added pressure and subtracted volume is given which holds true for real gases. The equation is -
\[\left( P+\dfrac{a{{n}^{2}}}{{{V}^{2}}} \right)\left( V-nb \right)=RT\]
COMPLETE STEP BY STEP SOLUTION: The ideal gas law equation is an equation of state variables of a hypothetical ideal gas. We know that the ideal gas equation is – PV = nRT where, P is the pressure, V is the volume of the gas, n is the number of moles, R is the universal gas constant which has a fixed value and T is the temperature.
However, for a real gas we make some changes to this ideal gas equation. We add a pressure term and subtract a volume term.
However, excluding the extra pressure term it is given as- P (V-b) = RT.
We know that the equation of a straight line is- y = mx + c
Where, m is the slope and c is the intercept and x and y depicts the two axes.
Rearranging equation P (V-b) = RT we can write that –
\[P=\dfrac{R}{(V-b)}T\]
Therefore, we have the relation between pressure and temperature for an isochoric curve.
Now if we compare this equation with the straight line equation we will see that the slope m is $\dfrac{R}{(V-b)}$ .
Hence, we can see from the above discussion that the slope of pressure against the temperature graph will be $\dfrac{R}{(V-b)}$.
Therefore, the correct answer is option [B] $\dfrac{R}{\left( V-b \right)}$.
NOTE: The ideal gas law equation is an equation of state variables of a hypothetical ideal gas. It has many limitations but still used for approximation of behaviour of a gas under certain conditions. It is a combination of Boyle’s law, Avogadro’s law, Charles’s law and Gay-Lussac’s law. Real gases do not obey the ideal gas law and therefore a gas equation for added pressure and subtracted volume is given which holds true for real gases. The equation is -
\[\left( P+\dfrac{a{{n}^{2}}}{{{V}^{2}}} \right)\left( V-nb \right)=RT\]
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

