
The Force of five hundred Newton acts on a body of mass five kilograms for ten seconds. The change in momentum of body is:
A. $1000{\text{N}}$
B. $25000{\text{N}}$
C. $10000{\text{N}}$
D. $5000{\text{N}}$
Answer
580.5k+ views
Hint: Momentum is equal to product of mass and velocity of the object and the rate of change of momentum means change in momentum with respect to time and is given by the formula force multiplied by time.
Complete step-by-step answer:
Formula used: $dp = F \times dt$
where $F$ is the force applied, $dp$ is the change in momentum and $dt$ is the time duration.
Given that,
$F = 500{\text{N}}$
Time $ = 10$seconds
As we know that, $dp = F \times dt$
Putting the values we get:
$
dp = 500 \times 10 \\
dp = 5000{\text{N}} \\
$
The change in momentum of the body is $5000{\text{N}}$.
Hence the correct option is D.
Note: According to Newton’s third law, the particles exert equal and opposite forces on each other therefore any change in momentum of one particle is balanced by the equal & opposite change of the momentum of another particle means in the absence of a net external force acting on a collection of particles than their total momentum never changes means the total momentum of a system remains constant.
Complete step-by-step answer:
Formula used: $dp = F \times dt$
where $F$ is the force applied, $dp$ is the change in momentum and $dt$ is the time duration.
Given that,
$F = 500{\text{N}}$
Time $ = 10$seconds
As we know that, $dp = F \times dt$
Putting the values we get:
$
dp = 500 \times 10 \\
dp = 5000{\text{N}} \\
$
The change in momentum of the body is $5000{\text{N}}$.
Hence the correct option is D.
Note: According to Newton’s third law, the particles exert equal and opposite forces on each other therefore any change in momentum of one particle is balanced by the equal & opposite change of the momentum of another particle means in the absence of a net external force acting on a collection of particles than their total momentum never changes means the total momentum of a system remains constant.
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