The following observations are arranged in ascending order:
$26,29,42,53,x,x+2,70,75,82,93$
If the median is $65$ , find the value of $x$.
A. $62$
B. $64$
C. $65$
D. $68$
Answer
554.4k+ views
Hint: Here we have been given a set of observations which are arranged in ascending order and there median is given we have to find the value of the unknown variable. Firstly we will write the formula for calculating median then by using that formula we will substitute the value in it. Finally we will solve the equation obtained and get our desired answer.
Complete step-by-step solution:
The observations is given as follows,
$26,29,42,53,x,x+2,70,75,82,93$…..$\left( 1 \right)$
Median is given as follows,
Median $=65$…..$\left( 2 \right)$
Now as we know median is calculated as follows,
Median $={{\dfrac{\left( n+1 \right)}{2}}^{th}}$ term (If total number of observation is odd)…..$\left( 3 \right)$
Median $=\dfrac{{{\dfrac{n}{2}}^{th}}\,term+{{\left( \dfrac{n}{2}+1 \right)}^{th}}term}{2}$ (If total number of observation is even)……$\left( 4 \right)$
On counting the number of terms in equation (1) we get,
$n=10$
So as the number of observation is even we will use formula in equation (4) as follows,
Median $=\dfrac{{{\left( \dfrac{10}{2} \right)}^{th}}term+{{\left( \dfrac{10}{2}+1 \right)}^{th}}term}{2}$
Median $=\dfrac{{{5}^{th}}term+{{6}^{th}}term}{2}$…$\left( 5 \right)$
Now from equation (1) the ${{5}^{th}}$ and ${{6}^{th}}$ terms are,
$26,29,42,53,\underline{x,x+2},70,75,82,93$
Put the value in equation (5) from equation (2) and above we get,
$\Rightarrow 65=\dfrac{x+x+2}{2}$
$\Rightarrow 65=\dfrac{2x+2}{2}$
Solving further we get,
$\Rightarrow 65\times 2=2x+2$
$\Rightarrow 130-2=2x$
Divide both sides by $2$
$\Rightarrow \dfrac{128}{2}=\dfrac{2x}{2}$
$\Rightarrow 64=x$
So we got the value of $x$ as $64$ .
Hence the correct option is (B).
Note: Median is the middle value of the given data set when we arrange them in ascending or descending order. It is one of the measures of central tendency the other two measures are the mean and mode. A median is that number that separates the higher half of the population by the lower half of the population in the given probability distribution. The formula to calculate the median when the number of observations is even or when they are odd is different and that should be kept in mind while solving these problems.
Complete step-by-step solution:
The observations is given as follows,
$26,29,42,53,x,x+2,70,75,82,93$…..$\left( 1 \right)$
Median is given as follows,
Median $=65$…..$\left( 2 \right)$
Now as we know median is calculated as follows,
Median $={{\dfrac{\left( n+1 \right)}{2}}^{th}}$ term (If total number of observation is odd)…..$\left( 3 \right)$
Median $=\dfrac{{{\dfrac{n}{2}}^{th}}\,term+{{\left( \dfrac{n}{2}+1 \right)}^{th}}term}{2}$ (If total number of observation is even)……$\left( 4 \right)$
On counting the number of terms in equation (1) we get,
$n=10$
So as the number of observation is even we will use formula in equation (4) as follows,
Median $=\dfrac{{{\left( \dfrac{10}{2} \right)}^{th}}term+{{\left( \dfrac{10}{2}+1 \right)}^{th}}term}{2}$
Median $=\dfrac{{{5}^{th}}term+{{6}^{th}}term}{2}$…$\left( 5 \right)$
Now from equation (1) the ${{5}^{th}}$ and ${{6}^{th}}$ terms are,
$26,29,42,53,\underline{x,x+2},70,75,82,93$
Put the value in equation (5) from equation (2) and above we get,
$\Rightarrow 65=\dfrac{x+x+2}{2}$
$\Rightarrow 65=\dfrac{2x+2}{2}$
Solving further we get,
$\Rightarrow 65\times 2=2x+2$
$\Rightarrow 130-2=2x$
Divide both sides by $2$
$\Rightarrow \dfrac{128}{2}=\dfrac{2x}{2}$
$\Rightarrow 64=x$
So we got the value of $x$ as $64$ .
Hence the correct option is (B).
Note: Median is the middle value of the given data set when we arrange them in ascending or descending order. It is one of the measures of central tendency the other two measures are the mean and mode. A median is that number that separates the higher half of the population by the lower half of the population in the given probability distribution. The formula to calculate the median when the number of observations is even or when they are odd is different and that should be kept in mind while solving these problems.
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

State BPT theorem and prove it class 10 maths CBSE

A peacock is sitting on the top of a pillar which -class-10-maths-CBSE

Railways Women Helpline Number?

Explain the refraction of light through a glassslab class 10 physics CBSE

a Why did Mendel choose pea plants for his experiments class 10 biology CBSE

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

10 examples of evaporation in daily life with explanations

What is the full form of POSCO class 10 social science CBSE

Write short note on buckyball class 10 chemistry CBSE

Write a report on a Bus accident class 10 english CBSE

Five things I will do to build a great India class 10 english CBSE

