
The equivalent weight of phosphoric acid ( ) in the reaction is:
A. 25
B. 49
C. 59
D. 98
Answer
446.1k+ views
2 likes
Hint: For calculation of equivalent weight, we should know the molar mass and “n” equivalent factor. For determination of equivalent weight of phosphoric acid we have to find “n”. And in phosphoric acid it is about replaceable hydrogen.
Step by step answer:
We can easily find the molar mass of
Molecular weight calculation
Number of H= 3 3 × 1 = 3
Number of P= 1 1 × 31 = 31
Number of O= 4 4 × 16 = 64
Molecular weight = 3 + 31 + 64= 98
Now we will find a number of equivalents that is “n”. Is acid so “n” it will have basicity.
2 hydrogen ions are left. Therefore, the valence factor = 2
= 49
Equivalent weight of is 49.
Additional information:
Equivalent weight of an acid: we should know that the valence factor of an acid is equal to its basicity. The basicity of an acid is equal to a replaceable hydrogen ion (proton) in its aqueous solution. Importantly, basicity is not the same as the number of hydrogen atoms in acid molecules. Consider acetic acid ( ). It contains 4 hydrogen atoms in it, but only 1 replaceable hydrogen ion. As such, the basicity of acetic acid is 1.
Note: We should understand the concept of finding the valence factor for acid and base. Phosphorus based acids like phosphoric acid ( ), phosphorous acid ( ) and hypo-phosphorous acid ( ) need special attention of us to understand their basicity. By looking at formula, it appears that these compounds may furnish OH ions, but bond strengths between phosphorus and oxygen (P-O) and phosphorus and hydrogen (P-H) are stronger than between oxygen and hydrogen (O-H) in –OH group. As such, these molecules release hydrogen ions from –OH group and behave as acid. Clearly, basicity of phosphoric acid ( ), phosphorous acid ( ) and hypo-phosphorous acid ( ) are 3, 2 and 1 respectively.
Step by step answer:
We can easily find the molar mass of
Molecular weight calculation
Number of H= 3
Number of P= 1
Number of O= 4
Molecular weight = 3 + 31 + 64= 98
Now we will find a number of equivalents that is “n”.
2 hydrogen ions are left. Therefore, the valence factor = 2
Equivalent weight of
Additional information:
Equivalent weight of an acid: we should know that the valence factor of an acid is equal to its basicity. The basicity of an acid is equal to a replaceable hydrogen ion (proton) in its aqueous solution. Importantly, basicity is not the same as the number of hydrogen atoms in acid molecules. Consider acetic acid (
Note: We should understand the concept of finding the valence factor for acid and base. Phosphorus based acids like phosphoric acid (
Latest Vedantu courses for you
Grade 11 Science PCM | CBSE | SCHOOL | English
CBSE (2025-26)
School Full course for CBSE students
₹41,848 per year
Recently Updated Pages
Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
Explain why it is said like that Mock drill is use class 11 social science CBSE

The non protein part of an enzyme is a A Prosthetic class 11 biology CBSE

Which of the following blood vessels in the circulatory class 11 biology CBSE

What is a zygomorphic flower Give example class 11 biology CBSE

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

The deoxygenated blood from the hind limbs of the frog class 11 biology CBSE
