
The equivalent function of $ \log {x^2} $ is
A. $ 2\log x $
B. $ 2\log \left| x \right| $
C. $ \left| {\log {x^2}} \right| $
D. $ {(\log x)^2} $
Answer
600k+ views
Hint: Here before solving this question we need to know the property of logarithm: -
$ \log {m^n} = n\log m\,\,\,\,\,\,\,\,\,\,...(1) $
There is no alternate method but to apply the property of log to get the required result.
Complete step-by-step answer:
In mathematics, the logarithm is the inverse function to exponentiation. That means the logarithm of a given number x is the exponent to which another fixed number, the base b, must be raised, to produce that number x.
According to this question we have,
$ \log {x^2} $
Since we know that logarithm takes only a positive number and we also know that property of $ {x^2} $ is whether there is a positive number or negative number the result is always positive in that case there will be a problem if negative values come into play.
So, in order to avoid the negative sign, we will use the modulus function.
$ m = x\,{\text{and}}\,n = 2 $
Substitute all the values in equation (1).
$ \log {x^2} = 2\log \left| x \right| $
So, the correct answer is “Option b”.
Note: In this question, there is a confusion between option a and option b. So in order to eliminate the option, we will use the basic definition of a domain.
$ \log {m^n} = n\log m\,\,\,\,\,\,\,\,\,\,...(1) $
There is no alternate method but to apply the property of log to get the required result.
Complete step-by-step answer:
In mathematics, the logarithm is the inverse function to exponentiation. That means the logarithm of a given number x is the exponent to which another fixed number, the base b, must be raised, to produce that number x.
According to this question we have,
$ \log {x^2} $
Since we know that logarithm takes only a positive number and we also know that property of $ {x^2} $ is whether there is a positive number or negative number the result is always positive in that case there will be a problem if negative values come into play.
So, in order to avoid the negative sign, we will use the modulus function.
$ m = x\,{\text{and}}\,n = 2 $
Substitute all the values in equation (1).
$ \log {x^2} = 2\log \left| x \right| $
So, the correct answer is “Option b”.
Note: In this question, there is a confusion between option a and option b. So in order to eliminate the option, we will use the basic definition of a domain.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Explain zero factorial class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

What steps did the French revolutionaries take to create class 11 social science CBSE

The transition element that has lowest enthalpy of class 11 chemistry CBSE

Can anyone list 10 advantages and disadvantages of friction

