
The equation of the line whose slope is $ 3 $ and which cuts off an intercept of $ 3 $ units from the positive x axis is:
(A) $ y = 3x - 9 $
(B) $ y = 3x + 3 $
(C) $ y = 3x + 9 $
(D) None of these
Answer
511.8k+ views
Hint: In the given problem, we are required to find the equation of a line whose slope is given to us and cuts off an intercept on the positive x axis as provided to us. We can easily find the equation of the line using the slope point form of a straight line. So, we first substitute the value of slope given to us and then substitute the coordinates of point given to us as positive x intercept of the straight line.
Complete step-by-step answer:
So, the slope of line \[ = m = 3\]
Also, we are given that the line cuts off an intercept of three units on the positive axis.
So, the point \[\left( {3,0} \right)\] lies on the required straight line.
Now, we know the slope point form of the line, where we can find the equation of a straight line given the slope of the line and the point lying on it. The slope point form of the line can be represented as: $ \left( {y - {y_1}} \right) = m\left( {x - {x_1}} \right) $ where $ \left( {{x_1},{y_1}} \right) $ is the point lying on the line given to us and m is the slope of the required straight line.
Considering $ {x_1} = 3 $ and $ {y_1} = 0 $ as the point given to us is \[\left( {3,0} \right)\]
Therefore, required equation of line is as follows:
$ (y - 0) = 3(x - 3) $
On opening the brackets and simplifying further, we get,
$ \Rightarrow y = 3x - 9 $
Hence, the equation of the straight line is: $ y = 3x - 9 $ .
Therefore, option (A) is the correct answer.
So, the correct answer is “Option A”.
Note: The given problem requires us to have thorough knowledge of the concepts of coordinate geometry. The equation of the straight line in all the forms must be remembered. The applications of concepts learnt in coordinate geometry are wide ranging. We should know that the y coordinate of any point lying on the x axis is always zero.
Complete step-by-step answer:
So, the slope of line \[ = m = 3\]
Also, we are given that the line cuts off an intercept of three units on the positive axis.
So, the point \[\left( {3,0} \right)\] lies on the required straight line.
Now, we know the slope point form of the line, where we can find the equation of a straight line given the slope of the line and the point lying on it. The slope point form of the line can be represented as: $ \left( {y - {y_1}} \right) = m\left( {x - {x_1}} \right) $ where $ \left( {{x_1},{y_1}} \right) $ is the point lying on the line given to us and m is the slope of the required straight line.
Considering $ {x_1} = 3 $ and $ {y_1} = 0 $ as the point given to us is \[\left( {3,0} \right)\]
Therefore, required equation of line is as follows:
$ (y - 0) = 3(x - 3) $
On opening the brackets and simplifying further, we get,
$ \Rightarrow y = 3x - 9 $
Hence, the equation of the straight line is: $ y = 3x - 9 $ .
Therefore, option (A) is the correct answer.
So, the correct answer is “Option A”.
Note: The given problem requires us to have thorough knowledge of the concepts of coordinate geometry. The equation of the straight line in all the forms must be remembered. The applications of concepts learnt in coordinate geometry are wide ranging. We should know that the y coordinate of any point lying on the x axis is always zero.
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
Draw a diagram of nephron and explain its structur class 11 biology CBSE

Explain zero factorial class 11 maths CBSE

Chemical formula of Bleaching powder is A Ca2OCl2 B class 11 chemistry CBSE

Name the part of the brain responsible for the precision class 11 biology CBSE

The growth of tendril in pea plants is due to AEffect class 11 biology CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

