Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store
seo-qna
SearchIcon
banner

The earth may be considered as a spherically shaped uniform core of density ρ1 and radius R2 surrounded by a uniform shell of thickness R2and density ρ2. Find the ratio ofρ1ρ2 if the acceleration due to gravity is the same as the surface as at depth R2 from the surface.

Answer
VerifiedVerified
480.3k+ views
1 likes
like imagedislike image
Hint: We know that the density of the earth varies with the depth. We need to understand the variation of the gravitational forces due to this density changes with depth caused by the change in mass to solve the ratio between the densities.

Complete answer:
We are given the two parts of the earth with different densities for which we have to find the ratio between the densities between them.
Now, we are given the densities of two parts of the earth. We can find their mass by using the relation between the mass, volume and density as –
Mass, m = Volume × Densitym=43πr3×ρ
Now, we can find the mass of each of the two parts of the earth.
(i)The mass of the core with radius R2 can be given as –
mcore=43π(R2)3×ρ1
(ii)The mass of the outer shell of radius R2 can be given as –
mshell=43π[R3(R2)3]×ρ2mshell=43π7R38×ρ2
We can find the total mass of the Earth from the above to as –
M=mcore+mshellM=43πR83×ρ1+43π7R38×ρ2M=4πR324(ρ1+7ρ2)
Now, we know that the acceleration due to gravity of the earth up to the half of the radius is ‘g’ itself. It can be given as –
g=GMR2g=G4πR3R224(ρ1+7ρ2)g=G4πR24(ρ1+7ρ2)
Now, the acceleration due to gravity at the half of the radius can be given as –
g=Gmr2g=G43π(R2)3×ρ1(R2)2g=G4πR6ρ1
Now, we can find the ratio between the two acceleration due to gravities to find the ratio between the densities of the two parts. According to the question, the acceleration due to gravity is the same for both. So, we can equate them as –
g=gG4πR6ρ1=G4πR24(ρ1+7ρ2)ρ1=ρ1+7ρ243ρ1=7ρ2ρ1ρ2=73
The ratio of the densities of the two parts of the earth is, therefore, given as 7:3.
This is the required solution.

Note:
The acceleration due to gravity of the earth is highly dependent on the depth of the earth from where it is considered. Here, we assume as per the question that the acceleration due to gravity remains constant up to half the radius, which is not practical.
Latest Vedantu courses for you
Grade 10 | CBSE | SCHOOL | English
Vedantu 10 CBSE Pro Course - (2025-26)
calendar iconAcademic year 2025-26
language iconENGLISH
book iconUnlimited access till final school exam
tick
School Full course for CBSE students
PhysicsPhysics
Social scienceSocial science
ChemistryChemistry
MathsMaths
BiologyBiology
EnglishEnglish
₹38,500 (9% Off)
₹35,000 per year
Select and buy