
The dimensions of Hubble constant is:
A. \[\left[ {{T}^{-1}} \right]\]
B. $\left[ {{M}^{0}}{{L}^{0}}{{T}^{-2}} \right]$
C. $\left[ ML{{T}^{4}} \right]$
D. $\left[ M{{T}^{-1}} \right]$
Answer
589.5k+ views
Hint: Hubble’s constant is a constant used in cosmology which shows how fast a galaxy recedes from us per second due to expansion of the universe. Simply speaking, it is a proportionality that relates to the velocity and displacement of the galaxies. Notice the term per second in the definition, it will give you an idea about the dimension of Hubble’s constant.
Complete Step-by-Step solution:
Hubble’s Constant is the byproduct of Hubble’s Law in physical cosmology which states that- ‘The galaxies are receding away from us at a velocity which is proportional to the distance from us’. Here the term ‘us’ means earth. So if the galaxy is very far away from us, the velocity of recession will also be faster.
We can write Hubble’s Law as simple equation as follows,
$\text{Velocity of the galaxy}=\text{Hubble Constant}\times \left( \text{Distance of the galaxy from earth} \right)$
So we know that the dimensional formula for the velocity is $\left[ L{{T}^{-1}} \right]$ and the dimensional formula for distance is $\left[ L \right]$. So the dimension formula for the Hubble’s constant can be written as,
$\text{Hubble }\!\!'\!\!\text{ s Constant}=\dfrac{\left[ \text{Velocity} \right]}{\left[ \text{Distance} \right]}=\dfrac{\left[ L{{T}^{-1}} \right]}{\left[ L \right]}$
$\therefore \text{Hubble }\!\!'\!\!\text{ s Constant}=\left[ {{T}^{-1}} \right]$
So the dimensional formula of the Hubble’s constant is found to be $\left[ {{T}^{-1}} \right]$.
So the answer to the question is option (A)- $\left[ {{T}^{-1}} \right]$.
Additional Information:
Edwin Hubble postulated his famous law in the 1920s which came to be later known as the Hubble’s law, which showed that the galaxies which are not in the milky way cluster receded away from with a velocity proportional to the distance away from the earth.
The value of Hubble’s constant has changed over the years because of better measurement techniques in determining the Redshift produced by the galaxies.
Note: The dimensional formula of the Hubble’s constant is the same as that of frequency and angular frequency.
The value of Hubble’s Constant has changed over the years. Initially it was $150\text{ }\dfrac{km}{\left( s\times Mpc \right)}$, where s is in seconds, pc stands for parsec which is a unit for distance in astronomy and cosmology.
The current value of Hubble's constant is approximately $\text{69 }\dfrac{km}{\left( s\times Mpc \right)}$.
Complete Step-by-Step solution:
Hubble’s Constant is the byproduct of Hubble’s Law in physical cosmology which states that- ‘The galaxies are receding away from us at a velocity which is proportional to the distance from us’. Here the term ‘us’ means earth. So if the galaxy is very far away from us, the velocity of recession will also be faster.
We can write Hubble’s Law as simple equation as follows,
$\text{Velocity of the galaxy}=\text{Hubble Constant}\times \left( \text{Distance of the galaxy from earth} \right)$
So we know that the dimensional formula for the velocity is $\left[ L{{T}^{-1}} \right]$ and the dimensional formula for distance is $\left[ L \right]$. So the dimension formula for the Hubble’s constant can be written as,
$\text{Hubble }\!\!'\!\!\text{ s Constant}=\dfrac{\left[ \text{Velocity} \right]}{\left[ \text{Distance} \right]}=\dfrac{\left[ L{{T}^{-1}} \right]}{\left[ L \right]}$
$\therefore \text{Hubble }\!\!'\!\!\text{ s Constant}=\left[ {{T}^{-1}} \right]$
So the dimensional formula of the Hubble’s constant is found to be $\left[ {{T}^{-1}} \right]$.
So the answer to the question is option (A)- $\left[ {{T}^{-1}} \right]$.
Additional Information:
Edwin Hubble postulated his famous law in the 1920s which came to be later known as the Hubble’s law, which showed that the galaxies which are not in the milky way cluster receded away from with a velocity proportional to the distance away from the earth.
The value of Hubble’s constant has changed over the years because of better measurement techniques in determining the Redshift produced by the galaxies.
Note: The dimensional formula of the Hubble’s constant is the same as that of frequency and angular frequency.
The value of Hubble’s Constant has changed over the years. Initially it was $150\text{ }\dfrac{km}{\left( s\times Mpc \right)}$, where s is in seconds, pc stands for parsec which is a unit for distance in astronomy and cosmology.
The current value of Hubble's constant is approximately $\text{69 }\dfrac{km}{\left( s\times Mpc \right)}$.
Recently Updated Pages
Two men on either side of the cliff 90m height observe class 10 maths CBSE

What happens to glucose which enters nephron along class 10 biology CBSE

Cutting of the Chinese melon means A The business and class 10 social science CBSE

Write a dialogue with at least ten utterances between class 10 english CBSE

Show an aquatic food chain using the following organisms class 10 biology CBSE

A circle is inscribed in an equilateral triangle and class 10 maths CBSE

Trending doubts
Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Which of the following does not have a fundamental class 10 physics CBSE

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

