
The dimensional formula for torque is
$
A.{\text{ M}}{{\text{L}}^2}{T^{ - 2}} \\
B.{\text{ M}}{{\text{L}}^{ - 1}}{T^{ - 1}} \\
C.{\text{ }}{{\text{L}}^2}{\text{ }}{{\text{T}}^{ - 1}} \\
D.{\text{ }}{{\text{M}}^2}{T^{ - 2}}{K^{ - 1}} \\
$
Answer
600.9k+ views
Hint:Here we will proceed by writing the formula of Torque that is Angular reaction $ \times $ Moment of Inertia. After expanding the formula, write the dimensional formulas of both angular reaction and moment of inertia , we can easily calculate the dimensional formula for torque.
Complete step-by-step answer:
Force causes acceleration and Torque causes angular accelerations. Torque is proportional to the distance between the rotation axis and the point of application of the force (the point at which the force is applied).
Mathematically, Torque is defined as a product of Angular acceleration and Moment of Inertia. Its formula is
Torque = Angular Acceleration $ \times $ Moment of Inertia …….(1)
Since, Moment of Inertia (M.O.I)= Radius of Gyration$^2$ $ \times $ Mass
Dimension formula of radius of gyration is ${L^2}$ and mass is ${M^1}$
Therefore, The dimensional formula of Moment of Inertia = ${M^1}{L^2}{T^0}$ …..(2)
And, Angular acceleration = Angular velocity $ \times $ Time$^{ - 1}$
Dimension formula of angular velocity is ${L^0}{T^{-1}}$ and time is ${T^{-1}}$
Therefore, the dimensional formula of Angular Acceleration = ${M^0}{L^0}{T^{ - 2}}$ …..(3)
On substituting equation (2) and (3) in equation (1) we get,
Torque= Moment of Inertia $ \times $ Angular Acceleration
Or, I =
$
\left[ {{M^1}{L^2}{T^0}} \right] \times \left[ {{M^0}{L^0}{T^{ - 2}}} \right] \\
= \left[ {M{\text{ }}{{\text{L}}^2}{T^{ - 2}}} \right] \\
$
Therefore, the torque is dimensionally represented as $\left[ {M{\text{ }}{{\text{L}}^2}{T^{ - 2}}} \right]$
Where, M= Mass
L = Length
T = Time
$\therefore $ C is the correct option.
Note- Dimensional formula is an expression for the unit of a physical quantity in terms of the fundamental quantities. The fundamental quantities are mass (M), length (L), and time (T). A dimensional formula is expressed in terms of powers of M,L and T.Whenever we come up with this type of problem where we are asked to find out the dimensional formula for torque. Then by using moment of inertia that is ${M^1}{L^2}{T^0}$ and angular acceleration that is ${M^0}{L^0}{T^{ - 2}}$ we can easily derive the dimensional formula for torque.
Complete step-by-step answer:
Force causes acceleration and Torque causes angular accelerations. Torque is proportional to the distance between the rotation axis and the point of application of the force (the point at which the force is applied).
Mathematically, Torque is defined as a product of Angular acceleration and Moment of Inertia. Its formula is
Torque = Angular Acceleration $ \times $ Moment of Inertia …….(1)
Since, Moment of Inertia (M.O.I)= Radius of Gyration$^2$ $ \times $ Mass
Dimension formula of radius of gyration is ${L^2}$ and mass is ${M^1}$
Therefore, The dimensional formula of Moment of Inertia = ${M^1}{L^2}{T^0}$ …..(2)
And, Angular acceleration = Angular velocity $ \times $ Time$^{ - 1}$
Dimension formula of angular velocity is ${L^0}{T^{-1}}$ and time is ${T^{-1}}$
Therefore, the dimensional formula of Angular Acceleration = ${M^0}{L^0}{T^{ - 2}}$ …..(3)
On substituting equation (2) and (3) in equation (1) we get,
Torque= Moment of Inertia $ \times $ Angular Acceleration
Or, I =
$
\left[ {{M^1}{L^2}{T^0}} \right] \times \left[ {{M^0}{L^0}{T^{ - 2}}} \right] \\
= \left[ {M{\text{ }}{{\text{L}}^2}{T^{ - 2}}} \right] \\
$
Therefore, the torque is dimensionally represented as $\left[ {M{\text{ }}{{\text{L}}^2}{T^{ - 2}}} \right]$
Where, M= Mass
L = Length
T = Time
$\therefore $ C is the correct option.
Note- Dimensional formula is an expression for the unit of a physical quantity in terms of the fundamental quantities. The fundamental quantities are mass (M), length (L), and time (T). A dimensional formula is expressed in terms of powers of M,L and T.Whenever we come up with this type of problem where we are asked to find out the dimensional formula for torque. Then by using moment of inertia that is ${M^1}{L^2}{T^0}$ and angular acceleration that is ${M^0}{L^0}{T^{ - 2}}$ we can easily derive the dimensional formula for torque.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

