The dimensional formula for the torque is
(a). \[M{{L}^{2}}{{T}^{-2}}\]
(b). \[M{{L}^{-1}}{{T}^{-1}}\]
(c). \[{{L}^{2}}{{T}^{-1}}\]
(d). \[{{M}^{2}}{{T}^{-2}}{{K}^{-1}}\]
Answer
655.5k+ views
- Hint: Torque is the product of angular acceleration and moment of inertia. We can simply calculate the dimensional formula of torque by putting the dimensional formulas of angular acceleration and moment of inertia in the respective equation.
Complete step-by-step solution -
The term force is used in the linear motions, while torques are used in the rotational motions, but they are having the same basis. Torque is proportional to the lever arm distance. i.e., the distance between the rotation axis and the force applied point. The formula of torque is given by,
Torque = angular acceleration x moment of inertia …………..(1).
The moment of inertia is = Mass x ${radius of gyration^2}$
Dimensional formula of moment of Inertia $=M{{L}^{2}}$
Angular acceleration = Angular velocity x time
Hence, the dimensional formula of angular acceleration will be, $={{T}^{-2}}$
On substituting these formulas in equation (1),
Dimensional formula of Torque will be,
$=\left[ {{M}^{1}}{{L}^{2}} \right]\times \left[ {{T}^{-2}} \right]$
$=\left[ {{M}^{1}}{{L}^{2}}{{T}^{-2}} \right]$
Where M is the mass, L is the length and T is the time
Hence the correct answer is option (A)
Note: When they are asking for dimensional formulas of any quantity, revise the expression of that quantity and put the dimensional formulas of substituent quantities in the solution, and develop the final dimensional formula.
Complete step-by-step solution -
The term force is used in the linear motions, while torques are used in the rotational motions, but they are having the same basis. Torque is proportional to the lever arm distance. i.e., the distance between the rotation axis and the force applied point. The formula of torque is given by,
Torque = angular acceleration x moment of inertia …………..(1).
The moment of inertia is = Mass x ${radius of gyration^2}$
Dimensional formula of moment of Inertia $=M{{L}^{2}}$
Angular acceleration = Angular velocity x time
Hence, the dimensional formula of angular acceleration will be, $={{T}^{-2}}$
On substituting these formulas in equation (1),
Dimensional formula of Torque will be,
$=\left[ {{M}^{1}}{{L}^{2}} \right]\times \left[ {{T}^{-2}} \right]$
$=\left[ {{M}^{1}}{{L}^{2}}{{T}^{-2}} \right]$
Where M is the mass, L is the length and T is the time
Hence the correct answer is option (A)
Note: When they are asking for dimensional formulas of any quantity, revise the expression of that quantity and put the dimensional formulas of substituent quantities in the solution, and develop the final dimensional formula.
Recently Updated Pages
Lysosomes are known as suicidal bags of cell why class 11 biology CBSE

Father s age is three times the sum of the ages of-class-11-maths-CBSE

Give a comparative account of the classes of kingdom class 11 biology CBSE

The ceiling of a long hall is 25m high What is the class 11 physics CBSE

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Name the Largest and the Smallest Cell in the Human Body ?

Trending doubts
Difference Between Prokaryotic Cells and Eukaryotic Cells

Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

10 examples of friction in our daily life

Draw a diagram of nephron and explain its structur class 11 biology CBSE

