Question

The difference in the place values of 8 between the smallest 4-digit numbers formed by using the digits, 3, 8, 0, 5 each only once is
a)8998 b) 6992 c.) 7992 d.)5998

Answer 1

Hint:- Using digits we will write the smallest and largest 4-digit number and then compare. Largest 4-digit no formed by 3, 8, 0, 5, is 8530.
     Smallest 4-digit no. formed by 3, 8, 0, 5 is 3058
Place value of a digit = (face value of the digit) × (value of the place).

Complete step-by-step answer:
Generally, the greatest 4-digit number is 9999:
and, the smallest 4-digit number is 1000.
But, we have to find the smallest and greatest 4-digit number using 3, 8, 0, 5.
So, greatest 4-digit number formed using digits 3, 8, 0, 5 = 8530
and, the smallest 4-digit number formed using digits 3, 8, 0, 5 is = 3058
Place value of digit ‘8’ in Greatest 4-digit number = 8000
Place value of 8 in smallest 4-digit number is = 8
$\therefore $ required difference = 8000 − 8 = $\boxed{7992}$

$\therefore $ option c is the correct answer.

Note:- In math, every digit in a number has a place value. Place value can be defined as the value represented by a digit in a number on the basis of its position in the number.
Place value of a digit = (face value of the digit) × (value of the place).
For example:- The place value of 6 in 64 is equals to 6 x 10 = 60.