
The diameter of a garden roller is 1.4 meter and it is 2 meter long. How much area will it cover in 50 revolutions?
Answer
625.2k+ views
Before solving this question, we must know the formula to find the area of the circle.
The formula to find the circumference of the circle - \[2\pi r\]
CIRCUMFERENCE: The circumference is the perimeter of a circle. That means that circumference of a circle is the length of the boundary of the circle.
Here is a rough figure of the roller.
Complete step-by-step answer:
The diameter of the roller = 1.4 meter
Radius of the roller = \[\dfrac{d}{2}=\text{ }\dfrac{1.4}{2}\text{ }=\text{ }0.7m\]
Length of the roller = 2 meter
Area covered by the roller in one revolution \[\begin{array}{*{35}{l}}
=2\pi rh=2\times \dfrac{22}{7}\times radius\times height \\
~=2\times \dfrac{22}{7}\times 0.7\times 2 \\
\end{array}\]
Area covered by the roller in 5 revolutions
\[\begin{array}{*{35}{l}}
=5\times 2\times \dfrac{22}{7}\times 0.7\times 2 \\
=10\times 0.7\times \dfrac{22}{7}\times 2 \\
=7\times \dfrac{22}{7}\times 2 \\
\begin{align}
& =22\times 2\text{ } \\
& =\text{ }44 \\
\end{align} \\
\end{array}\]
Therefore, the area covered by the roller in 5 revolutions is 44 square meter, i.e. \[44\text{ }{{m}^{2}}\] .
NOTE:-
The student must do the calculations very carefully. Any mistake in the calculations can make the answer wrong. Also, one must remember the formula to obtain the areas of different polygons as they can come in handy.
The formula to find the circumference of the circle - \[2\pi r\]
CIRCUMFERENCE: The circumference is the perimeter of a circle. That means that circumference of a circle is the length of the boundary of the circle.
Here is a rough figure of the roller.
Complete step-by-step answer:
The diameter of the roller = 1.4 meter
Radius of the roller = \[\dfrac{d}{2}=\text{ }\dfrac{1.4}{2}\text{ }=\text{ }0.7m\]
Length of the roller = 2 meter
Area covered by the roller in one revolution \[\begin{array}{*{35}{l}}
=2\pi rh=2\times \dfrac{22}{7}\times radius\times height \\
~=2\times \dfrac{22}{7}\times 0.7\times 2 \\
\end{array}\]
Area covered by the roller in 5 revolutions
\[\begin{array}{*{35}{l}}
=5\times 2\times \dfrac{22}{7}\times 0.7\times 2 \\
=10\times 0.7\times \dfrac{22}{7}\times 2 \\
=7\times \dfrac{22}{7}\times 2 \\
\begin{align}
& =22\times 2\text{ } \\
& =\text{ }44 \\
\end{align} \\
\end{array}\]
Therefore, the area covered by the roller in 5 revolutions is 44 square meter, i.e. \[44\text{ }{{m}^{2}}\] .
NOTE:-
The student must do the calculations very carefully. Any mistake in the calculations can make the answer wrong. Also, one must remember the formula to obtain the areas of different polygons as they can come in handy.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Class 10 Question and Answer - Your Ultimate Solutions Guide

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Trending doubts
Which country won the ICC Men's ODI World Cup in 2023?

In cricket, how many legal balls are there in a standard over?

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

What does "powerplay" mean in limited-overs cricket?

What is the full form of PNG A Petrol Natural Gas B class 10 chemistry CBSE

What is the "Powerplay" in T20 cricket?

