The decreasing order of priority of the following functional group is:
$1.ROH$
$2.RC \equiv CR$
$3.ROR$
$4.RN{H_2}$
A. $4 > 1 > 2 > 3$
B. $4 > 1 > 3 > 2$
C. $1 > 4 > 3 > 2$
D. $2 > 3 > 4 > 1$
Answer
576.6k+ views
Hint: The priority of an organic compound in chemistry can be determined by the oxidation number of the central carbon atom, greater the oxidation state of central carbon higher is its place in priority. For example, carboxylic acid has the highest priority.
Complete step by step answer:
In IUPAC nomenclature organic compounds are differentiated in different functional groups attached to the compound, different classes of compound therefore have different chemical and physical properties. If a compound contains two different functional groups then higher priority functional is considered to name the organic compound and the other functional group is considered as substitute.
Now, the priority order of the functional group is determined by the oxidation state of the central carbon atom, higher the oxidation state higher is its priority in the series of functional groups.
Now, by considering oxidation states of all functional group, we get below order of priority in decreasing order:
1. Carboxylic acid: $RCOOH${highest priority}
2. Derivatives of carboxylic acid:
${(RCO)_2}O > RCOOR > RCOX > RCON{H_2} > RC \equiv N$
(anhydride) (esters) (acid halide) (amides) (nitriles)
3. Oxygen and nitrogen containing group
$RCHO > RCOR > ROH > RN{H_2} > ROR$
(aldehydes) (ketone) (alcohol) (amines) (ester)
4. Alkenes and alkynes:
$RCH = C{H_2} > RC \equiv CH$
(alkenes) (alkynes)
5. Least priority:
$R - > RO - > X - $
(alkyl) (alkoxy) (halide)
From the above order of priority we can say that alcohol has the highest priority, after that amines, then ether and then alkynes has the least priority.
So decreasing order of priority from the question is;
‘C. $1 > 4 > 3 > 2$’.
Note: This is a trick you can use to find priority faster. Calculate the molecular mass of all the compounds, and arrange them in order of their molecular mass, except some exceptions this order will be exactly the same as the priority order of these compounds.
Complete step by step answer:
In IUPAC nomenclature organic compounds are differentiated in different functional groups attached to the compound, different classes of compound therefore have different chemical and physical properties. If a compound contains two different functional groups then higher priority functional is considered to name the organic compound and the other functional group is considered as substitute.
Now, the priority order of the functional group is determined by the oxidation state of the central carbon atom, higher the oxidation state higher is its priority in the series of functional groups.
Now, by considering oxidation states of all functional group, we get below order of priority in decreasing order:
1. Carboxylic acid: $RCOOH${highest priority}
2. Derivatives of carboxylic acid:
${(RCO)_2}O > RCOOR > RCOX > RCON{H_2} > RC \equiv N$
(anhydride) (esters) (acid halide) (amides) (nitriles)
3. Oxygen and nitrogen containing group
$RCHO > RCOR > ROH > RN{H_2} > ROR$
(aldehydes) (ketone) (alcohol) (amines) (ester)
4. Alkenes and alkynes:
$RCH = C{H_2} > RC \equiv CH$
(alkenes) (alkynes)
5. Least priority:
$R - > RO - > X - $
(alkyl) (alkoxy) (halide)
From the above order of priority we can say that alcohol has the highest priority, after that amines, then ether and then alkynes has the least priority.
So decreasing order of priority from the question is;
‘C. $1 > 4 > 3 > 2$’.
Note: This is a trick you can use to find priority faster. Calculate the molecular mass of all the compounds, and arrange them in order of their molecular mass, except some exceptions this order will be exactly the same as the priority order of these compounds.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Which among the following are examples of coming together class 11 social science CBSE

