
The curved surface area of a cylinder is $176\,\,c{m^2}$ and its base area $38.5\,\,c{m^2}$ .Find the volume of the cylinder and justify your answer.
Answer
586.5k+ views
Hint:
If r be the radius of the circular base and h be the height of the cylinder, then the volume is. $\pi {r^2}h$. And the curved surface area is $2\pi rh$ and base area is $\pi {r^2}$.
Complete step by step solution:
Step1:Since, the curved surface area of the cylinder is $176\,\,c{m^2}$ then
$2\pi rh = 176$ …………….(1)
Step2:The base area is $38.5\,\,c{m^2}$ ,then
$\pi {r^2} = 38.5$ ……………..(2)
Step3:From equation (1),
$r = \dfrac{{176}}{{2\pi h}}$ ……………………(3)
Step4:Putting this value of r into (2),
$\eqalign{
& \pi {\left( {\dfrac{{176}}{{2\pi h}}} \right)^2} = 38.5 \cr
& or, {h^2} = \dfrac{{{{88}^2}}}{{\pi \times 38.5}} = 64.026(approx) \cr
& or, h = 8.002(approx) \cr} $
Step5:Then the volume of the cylinder will be
$\eqalign{
& = \pi {r^2}h \cr
& = 38.5 \times 8.002 \cr
& = 308.08\,\,c{m^3}(approx.) \cr} $
Here the volume of the cylinder is $308.8\,\,c{m^3}$. Approximately.
Note:
If we check for the circular base radius r,put the value of h in equation (3). Then ..$r = \dfrac{{176}}{{2\pi \times 8.002}} = 3.5\,\,cm(approx.)$.
If r be the radius of the circular base and h be the height of the cylinder, then the volume is. $\pi {r^2}h$. And the curved surface area is $2\pi rh$ and base area is $\pi {r^2}$.
Complete step by step solution:
Step1:Since, the curved surface area of the cylinder is $176\,\,c{m^2}$ then
$2\pi rh = 176$ …………….(1)
Step2:The base area is $38.5\,\,c{m^2}$ ,then
$\pi {r^2} = 38.5$ ……………..(2)
Step3:From equation (1),
$r = \dfrac{{176}}{{2\pi h}}$ ……………………(3)
Step4:Putting this value of r into (2),
$\eqalign{
& \pi {\left( {\dfrac{{176}}{{2\pi h}}} \right)^2} = 38.5 \cr
& or, {h^2} = \dfrac{{{{88}^2}}}{{\pi \times 38.5}} = 64.026(approx) \cr
& or, h = 8.002(approx) \cr} $
Step5:Then the volume of the cylinder will be
$\eqalign{
& = \pi {r^2}h \cr
& = 38.5 \times 8.002 \cr
& = 308.08\,\,c{m^3}(approx.) \cr} $
Here the volume of the cylinder is $308.8\,\,c{m^3}$. Approximately.
Note:
If we check for the circular base radius r,put the value of h in equation (3). Then ..$r = \dfrac{{176}}{{2\pi \times 8.002}} = 3.5\,\,cm(approx.)$.
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Trending doubts
What is the median of the first 10 natural numbers class 10 maths CBSE

Which women's tennis player has 24 Grand Slam singles titles?

Who is the Brand Ambassador of Incredible India?

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

