
The conversion of PGA to PGAL during Calvin cycle is a process of
a) Reduction
b) Oxidation
c) Hydroxylation
d) Isomerization
Answer
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Hint: All photosynthetic plants go through the Calvin cycle. Let's go through each of the three phases of the Calvin cycle. Sucrose is produced and stored by plants as starch. To produce sucrose, the Calvin cycle goes through three major steps: carboxylation, decrease, and recovery. Various items are created during each progression. The Calvin cycle is made up of various chain reactions that result in the formation of sucrose.
Complete answer:
In the Calvin cycle, the carboxylation step is accomplished by the chemical, ribulose-1,5-bisphosphate carboxylase/oxygenase, otherwise called (\[rubisco\]). This protein joins carbon dioxide disintegrated in the cytosol with \[ribulose-1,5-bisphosphate\](\[RuBP\]) to create \[3-phosphoglycerate\](\[3-PGA\]). The \[3-phosphoglycerate\text{ }kinase\]adds a phosphate from \[ATP\] to the \[3-PGA\]to make \[1,3-bisphosphoglycerate\]. At that point \[NADP\]which states for Nicotinamide adenine dinucleotide phosphate eliminates hydrogen from \[NADPH\]and adds it to the \[1,3-bisphosphoglycerate\]to make \[glyceraldehyde-3-phosphate\](\[PGAL\]). Thus, \[PGAL\] is shaped by the expansion of \[{{H}_{2}}\]molecules and thus this response is called a reduction response.
Hence, option A-Reduction is the correct answer.
Additional Information:
\[RuBP\] carboxylation is the first stage (\[Rubisco\text{ }bisphosphate\]). In which the climatic \[C{{O}_{\text{ }2}}\] balances out with RuBP to form a stable natural halfway point. This reaction is completed by the chemical RuBP carboxylase, which produces two particles of 3-phosphoglycerate. The following stage is reduction. In this cycle, two atoms of\[ATP\]are used for phosphorylation and two atoms of \[~NADPH\]are used for decrease for each \[C{{O}_{\text{ }2}}\]\[Glyceraldehyde-3-phosphate\]or \[phosphoglyceraldehyde\]is formed from \[3-phosphoglycerate\].
Note:
Because it goes through recovery, the recovered \[RuBP\]cannot be the final result. As a result, the final item should be \[PGAL\]. The final item will be sucrose rather than glucose because plants cannot transport glucose directly to capacity. Sucrose can be shipped in plant stems because it is a non-reducing sugar that does not respond to oxygen while in the stem for capacity. During torpidity, the stored sucrose can be used.
Complete answer:
In the Calvin cycle, the carboxylation step is accomplished by the chemical, ribulose-1,5-bisphosphate carboxylase/oxygenase, otherwise called (\[rubisco\]). This protein joins carbon dioxide disintegrated in the cytosol with \[ribulose-1,5-bisphosphate\](\[RuBP\]) to create \[3-phosphoglycerate\](\[3-PGA\]). The \[3-phosphoglycerate\text{ }kinase\]adds a phosphate from \[ATP\] to the \[3-PGA\]to make \[1,3-bisphosphoglycerate\]. At that point \[NADP\]which states for Nicotinamide adenine dinucleotide phosphate eliminates hydrogen from \[NADPH\]and adds it to the \[1,3-bisphosphoglycerate\]to make \[glyceraldehyde-3-phosphate\](\[PGAL\]). Thus, \[PGAL\] is shaped by the expansion of \[{{H}_{2}}\]molecules and thus this response is called a reduction response.
Hence, option A-Reduction is the correct answer.
Additional Information:
\[RuBP\] carboxylation is the first stage (\[Rubisco\text{ }bisphosphate\]). In which the climatic \[C{{O}_{\text{ }2}}\] balances out with RuBP to form a stable natural halfway point. This reaction is completed by the chemical RuBP carboxylase, which produces two particles of 3-phosphoglycerate. The following stage is reduction. In this cycle, two atoms of\[ATP\]are used for phosphorylation and two atoms of \[~NADPH\]are used for decrease for each \[C{{O}_{\text{ }2}}\]\[Glyceraldehyde-3-phosphate\]or \[phosphoglyceraldehyde\]is formed from \[3-phosphoglycerate\].
Note:
Because it goes through recovery, the recovered \[RuBP\]cannot be the final result. As a result, the final item should be \[PGAL\]. The final item will be sucrose rather than glucose because plants cannot transport glucose directly to capacity. Sucrose can be shipped in plant stems because it is a non-reducing sugar that does not respond to oxygen while in the stem for capacity. During torpidity, the stored sucrose can be used.
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