
The conversion of ozone into oxygen is exothermic under what conditions is ozone the most stable?
Option:
(A) At low pressure & low temperature
(B) At high pressure & high temperature
(C) At high pressure & low temperature
(D) At low pressure & high temperature
Answer
486.3k+ views
Hint: Try to write the reaction of ozone converting to oxygen & use the concept of Le-chateler’s principle to predict under what conditions ozone will be more stable
Complete solution:
First, we will write the reaction of how ozone converts into oxygen.
Now, here we will use the concept of le- chateler’s principle to determine at what conditions ozone will be stated.
Here, we want the reaction to proceed in a backward direction i.e. towards formation of ozone. i.e. a side where it has fewer moles.
Now, Le- chateler’s principle states that when a pressure increases during a reaction shifts to that direction with fewer numbers of moles.
Hence, ozone has 2 moles & ${{\text{O}}_{\text{2}}}$ has 3 moles. So, an increase of pressure will be favourable for the formation and stability of ozone.
Now, talking about the temperature, this reaction ${20_3}\, \rightleftharpoons \,{30_2}$is an exothermic reaction i.e. heat is released.
Which implies ${20_3}\, \rightleftharpoons \,{30_2}$ will definitely be a endothermic reaction, Now, according to Le-chatelier’s principle, increase of temperature will cause the equilibrium to shift to from the endothermic reaction.
Therefore high temperatures are favourable for the stability of ozone.
High temperature & high pressures one suitable for use stability of ozone
Correct option (B) High temperature & high pressure.
Note: Ozone can also be prepared in the laboratory in two ways: corona discharge & UV ozone generators. Ozone layers are very important to us as it helps save us from harmful UV rays coming from the sun.
Complete solution:
First, we will write the reaction of how ozone converts into oxygen.
Reaction: ${20_3}\, \rightleftharpoons \,{30_2}$
$ \Rightarrow $ 2 moles of ozone will convert into 3 moles of oxygen.
Now, here we will use the concept of le- chateler’s principle to determine at what conditions ozone will be stated.
Here, we want the reaction to proceed in a backward direction i.e. towards formation of ozone. i.e. a side where it has fewer moles.
Now, Le- chateler’s principle states that when a pressure increases during a reaction shifts to that direction with fewer numbers of moles.
Hence, ozone has 2 moles & ${{\text{O}}_{\text{2}}}$ has 3 moles. So, an increase of pressure will be favourable for the formation and stability of ozone.
Now, talking about the temperature, this reaction ${20_3}\, \rightleftharpoons \,{30_2}$is an exothermic reaction i.e. heat is released.
Which implies ${20_3}\, \rightleftharpoons \,{30_2}$ will definitely be a endothermic reaction, Now, according to Le-chatelier’s principle, increase of temperature will cause the equilibrium to shift to from the endothermic reaction.
Therefore high temperatures are favourable for the stability of ozone.
High temperature & high pressures one suitable for use stability of ozone
Correct option (B) High temperature & high pressure.
Note: Ozone can also be prepared in the laboratory in two ways: corona discharge & UV ozone generators. Ozone layers are very important to us as it helps save us from harmful UV rays coming from the sun.
Recently Updated Pages
Master Class 11 Accountancy: Engaging Questions & Answers for Success

Glucose when reduced with HI and red Phosphorus gives class 11 chemistry CBSE

The highest possible oxidation states of Uranium and class 11 chemistry CBSE

Find the value of x if the mode of the following data class 11 maths CBSE

Which of the following can be used in the Friedel Crafts class 11 chemistry CBSE

A sphere of mass 40 kg is attracted by a second sphere class 11 physics CBSE

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

State and prove Bernoullis theorem class 11 physics CBSE

What organs are located on the left side of your body class 11 biology CBSE

Write down 5 differences between Ntype and Ptype s class 11 physics CBSE
