
The condensed formula of propene is:
A. ${H_3}C - C{H_2} - C{H_3}$
B. ${H_2}C - C{H_3} - C{H_3}$
C. ${H_3}C - CH = C{H_2}$
D. ${H_2}C - C{H_3} - C{H_2}$
Answer
557.7k+ views
Hint:Firstly by the basic rules of the IUPAC naming we get the rules followed for the correct naming process. Now these rules are, following priority order, the arrangement of the groups in the right alphabetical order for the sake of naming and to deduce the numbering by chief functional group. By following this we will get that the formula should have a double bond and $3$ carbon atoms. Which makes the right formula as ${H_3}C - CH = C{H_2}$ .
Complete step by step answer:In the given question we have to find out the correct formula by the IUPAC naming of the compound given in the problem statement.
Here we have to firstly take many of the things into the account:
The correct IUPAC naming is governed by various simple and useful rules which are given by the naming committee.
Some of them are :
1-While naming the priority order should be taken into account.
2-Apart from that we have to arrange the components in the alphabetical order when we have to write them in the IUPAC naming.
3-To start the numbering the beginning is with the carbon with the functional group with the highest priority in the priority order.
In basic naming these rules are almost all we need to govern the naming process. This is not a branched compound and the carbons in the functional chain are $3$ so the prefix would be butan.
Apart from that we can say that the compound is an alkene as the suffix ene suggests.
Now by that we will get the correct formula as the ${C_n}{H_{2n}}$ , which makes it to ${C_3}{H_6}$ .
Now that makes it as ${H_3}C - CH = C{H_2}$ .
So the correct option would be option C, ${H_3}C - CH = C{H_2}$ .
Note:Propene, also known as propylene or methyl ethylene, is an unsaturated organic compound with the chemical formula . It has one double bond, and is the second simplest member of the alkene class of hydrocarbons. It is a colorless gas with a faint petroleum-like odor.
Complete step by step answer:In the given question we have to find out the correct formula by the IUPAC naming of the compound given in the problem statement.
Here we have to firstly take many of the things into the account:
The correct IUPAC naming is governed by various simple and useful rules which are given by the naming committee.
Some of them are :
1-While naming the priority order should be taken into account.
2-Apart from that we have to arrange the components in the alphabetical order when we have to write them in the IUPAC naming.
3-To start the numbering the beginning is with the carbon with the functional group with the highest priority in the priority order.
In basic naming these rules are almost all we need to govern the naming process. This is not a branched compound and the carbons in the functional chain are $3$ so the prefix would be butan.
Apart from that we can say that the compound is an alkene as the suffix ene suggests.
Now by that we will get the correct formula as the ${C_n}{H_{2n}}$ , which makes it to ${C_3}{H_6}$ .
Now that makes it as ${H_3}C - CH = C{H_2}$ .
So the correct option would be option C, ${H_3}C - CH = C{H_2}$ .
Note:Propene, also known as propylene or methyl ethylene, is an unsaturated organic compound with the chemical formula . It has one double bond, and is the second simplest member of the alkene class of hydrocarbons. It is a colorless gas with a faint petroleum-like odor.
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