
The comparatively high boiling point of HF is due to :
A. High reactivity of fluorine
B. Small size of hydrogen atom
C. Formation of hydrogen bonds
D. High IE of fluorine
Answer
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Hint: Intermolecular bonding is the compound property of a particle to join to another atom. There are a few sorts of synthetic bonds like Covalent bonds, Ionic bonds, Hydrogen bonds, Metallic bonds, and Van der Waals cooperation.
Complete step by step solution:
a. The intermolecular bonding for \[HF\] is van der Waals, though for , \[HCl\] the intermolecular holding is hydrogen. Since the van der Waals bond is more grounded than hydrogen, HF will have a higher bubbling temperature.
b. The intermolecular holding for \[HF\] is covalent, though for, \[HCl\] the intermolecular holding is hydrogen. Since the covalent bond is more grounded than van der Waals, HF will have a higher bubbling temperature.
c. The intermolecular holding for \[HF\] is hydrogen, though for \[HCl\] the intermolecular holding is van der Waals. Since the hydrogen bond is more grounded than van der Waals, \[HF\] will have a higher bubbling temperature.
d. The nuclear number for \[Cl\] is more noteworthy than for \[F\] ,so \[HF\] will have a higher bubbling temperature.
The little size of the particle is significant in making the impact of the core more noteworthy. Henceforth fluorine has a high electron fondness (for the main electron to be included). Just chlorine has a higher electron fondness.
So, this question has multiple correct answers A,B,C
Note:
Fluorine is the most electronegative element because it has 5 electrons in it's 2P shell. The optimal electron configuration of the 2P orbital contains 6 electrons, so since Fluorine is so close to ideal electron configuration, the electrons are held very tightly to the nucleus.
Complete step by step solution:
a. The intermolecular bonding for \[HF\] is van der Waals, though for , \[HCl\] the intermolecular holding is hydrogen. Since the van der Waals bond is more grounded than hydrogen, HF will have a higher bubbling temperature.
b. The intermolecular holding for \[HF\] is covalent, though for, \[HCl\] the intermolecular holding is hydrogen. Since the covalent bond is more grounded than van der Waals, HF will have a higher bubbling temperature.
c. The intermolecular holding for \[HF\] is hydrogen, though for \[HCl\] the intermolecular holding is van der Waals. Since the hydrogen bond is more grounded than van der Waals, \[HF\] will have a higher bubbling temperature.
d. The nuclear number for \[Cl\] is more noteworthy than for \[F\] ,so \[HF\] will have a higher bubbling temperature.
The little size of the particle is significant in making the impact of the core more noteworthy. Henceforth fluorine has a high electron fondness (for the main electron to be included). Just chlorine has a higher electron fondness.
So, this question has multiple correct answers A,B,C
Note:
Fluorine is the most electronegative element because it has 5 electrons in it's 2P shell. The optimal electron configuration of the 2P orbital contains 6 electrons, so since Fluorine is so close to ideal electron configuration, the electrons are held very tightly to the nucleus.
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