
The CGS unit of pressure is 10cm times greater than the MKS unit of pressure.
A. True
B. False
Answer
507.6k+ views
Hint: The CGS system is given in centimeters and grams and the MKS in meters and kilograms. The unit of time is the only unit that is similar in both the systems. The CGS system uses smaller units to define its quantities as compared to the MKS system units.
Complete step by step answer:
The CGS system is the abbreviation for “centimeter gram second”. It uses centimeter as the unit of length, gram as the unit of mass and second as the unit of time. On the other hand, MKS system is the abbreviation for meter “kilogram second” system. It uses meter as the unit of length, kilogram as the unit of mass and second as the unit of time.
The CGS unit of pressure is dyne per centimeter squared (\[dyne/c{m^2}\] ) whereas the MKS unit of pressure is Pascal. Pascal is also the pressure on one Newton per meter squared (\[N/{m^2}\] ).
The relation between dyne and Newton is that: \[1N = {10^5}dyne\]
The relation between meter and centimeter is: \[1m = 100cm\]
So, \[\dfrac{N}{{{m^2}}} = \dfrac{{{{10}^5}dyne}}{{{{({{10}^3}cm)}^2}}} = \dfrac{{{{10}^5}dyne}}{{{{10}^6}c{m^2}}} = 10dyne/c{m^2}\]
Therefore, the MKS unit of pressure is ten times greater than the GCS unit of pressure. Thus, the above mentioned statement is false.
So, the correct answer is “Option B”.
Note:
one can say that \[1Pascal\] is equal to\[10dyne/c{m^2}\] . That is, \[1dyne/c{m^2}\] represents 10 times less pressure than\[1Pascal\] . In the CGS unit of pressure, the force of \[10dyne\] is applied to an area that is centimeters. And, in the MKS unit of pressure, the force of \[1N\] is applied to an area that is in meters.
Complete step by step answer:
The CGS system is the abbreviation for “centimeter gram second”. It uses centimeter as the unit of length, gram as the unit of mass and second as the unit of time. On the other hand, MKS system is the abbreviation for meter “kilogram second” system. It uses meter as the unit of length, kilogram as the unit of mass and second as the unit of time.
The CGS unit of pressure is dyne per centimeter squared (\[dyne/c{m^2}\] ) whereas the MKS unit of pressure is Pascal. Pascal is also the pressure on one Newton per meter squared (\[N/{m^2}\] ).
The relation between dyne and Newton is that: \[1N = {10^5}dyne\]
The relation between meter and centimeter is: \[1m = 100cm\]
So, \[\dfrac{N}{{{m^2}}} = \dfrac{{{{10}^5}dyne}}{{{{({{10}^3}cm)}^2}}} = \dfrac{{{{10}^5}dyne}}{{{{10}^6}c{m^2}}} = 10dyne/c{m^2}\]
Therefore, the MKS unit of pressure is ten times greater than the GCS unit of pressure. Thus, the above mentioned statement is false.
So, the correct answer is “Option B”.
Note:
one can say that \[1Pascal\] is equal to\[10dyne/c{m^2}\] . That is, \[1dyne/c{m^2}\] represents 10 times less pressure than\[1Pascal\] . In the CGS unit of pressure, the force of \[10dyne\] is applied to an area that is centimeters. And, in the MKS unit of pressure, the force of \[1N\] is applied to an area that is in meters.
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