
The bulk modulus of rubber is $9.8 \times {10^8}{\text{ }}\dfrac{N}{{{m^2}}}$. To what depth should a rubber ball be taken in a lake so that its volume is decreased by $0.1\% $ ?
A. $1{\text{ }}m$
B. ${\text{25 }}m$
C. $100{\text{ }}m$
D. ${\text{200 }}m$
Answer
435.9k+ views
Hint: First of all, we have to consider the volume of the rubber ball that it initially remains. Then by using the values here, we will find the new volume. After that by using the formula of bulk modulus we will find the answer to the solution.
Complete step by step answer:
Bulk Modulus also known as incompressibility refers to the measure of the ability of a substance to overcome changes in its volume when external pressure acts on it. The SI unit of bulk modulus is Pascal or $\dfrac{N}{{{m^2}}}$. Let the initial volume of the rubber ball be $V$.As, the volume decreases by $0.1\% $, then the final volume $V'$ corresponds to,
$V' = V - \dfrac{V}{{1000}} = \dfrac{{999}}{{1000}}V$
The relation between bulk modulus and change in volume is,
$k = \dfrac{P}{{ - \dfrac{{\Delta V}}{V}}} - - - - - \left( 1 \right)$
The variables are referred to,
$k = $ bulk modulus
$P = $ Pressure
$\Delta V = $ Change in volume$ = $ Final volume$ - $ Initial volume
$V = $ Initial volume
Pressure is given as the formula,
$P = \rho gh$
where $P = $ Pressure, $\rho = $ density of water, $g = $ acceleration due to gravity and $h = $ height.
Density of water is ${10^3}{\text{ }}\dfrac{{kg}}{{{m^3}}}$ and acceleration due to gravity is $9.8{\text{ }}\dfrac{m}{{{s^2}}}$.
The values given in the questions are,
$k = 9.8 \times {10^8}{\text{ }}\dfrac{N}{{{m^2}}}$
$\Rightarrow P = {10^3} \times 9.8 \times h$
$\Rightarrow \Delta V = \dfrac{{999}}{{1000}}V - V = - \dfrac{V}{{1000}}$
Substituting all the values in equation $\left( 1 \right)$ we get,
$9.8 \times {10^8} = - \dfrac{{{{10}^3} \times 9.8 \times h}}{{\dfrac{{ - \dfrac{V}{{1000}}}}{V}}}$
After cancelling the term 9.8 and $V$ we get,
$h= \dfrac{10^8}{10^6}$
$\therefore h = 100$
If the ball is taken at a depth of $100{\text{ }}m$ then the volume of the rubber ball will be decreased by $0.1\% $.
Hence, the correct answer is option C.
Note: It must be noted that the bulk modulus or incompressibility is a negative value because the volume of the material gets decreased than its initial volume. It is actually the ratio of amount of bulk stress to bulk strain. Bulk stress is pressure as pressure is the force that is applied upon a particular area. Bulk strain is changed in volume to original volume.
Complete step by step answer:
Bulk Modulus also known as incompressibility refers to the measure of the ability of a substance to overcome changes in its volume when external pressure acts on it. The SI unit of bulk modulus is Pascal or $\dfrac{N}{{{m^2}}}$. Let the initial volume of the rubber ball be $V$.As, the volume decreases by $0.1\% $, then the final volume $V'$ corresponds to,
$V' = V - \dfrac{V}{{1000}} = \dfrac{{999}}{{1000}}V$
The relation between bulk modulus and change in volume is,
$k = \dfrac{P}{{ - \dfrac{{\Delta V}}{V}}} - - - - - \left( 1 \right)$
The variables are referred to,
$k = $ bulk modulus
$P = $ Pressure
$\Delta V = $ Change in volume$ = $ Final volume$ - $ Initial volume
$V = $ Initial volume
Pressure is given as the formula,
$P = \rho gh$
where $P = $ Pressure, $\rho = $ density of water, $g = $ acceleration due to gravity and $h = $ height.
Density of water is ${10^3}{\text{ }}\dfrac{{kg}}{{{m^3}}}$ and acceleration due to gravity is $9.8{\text{ }}\dfrac{m}{{{s^2}}}$.
The values given in the questions are,
$k = 9.8 \times {10^8}{\text{ }}\dfrac{N}{{{m^2}}}$
$\Rightarrow P = {10^3} \times 9.8 \times h$
$\Rightarrow \Delta V = \dfrac{{999}}{{1000}}V - V = - \dfrac{V}{{1000}}$
Substituting all the values in equation $\left( 1 \right)$ we get,
$9.8 \times {10^8} = - \dfrac{{{{10}^3} \times 9.8 \times h}}{{\dfrac{{ - \dfrac{V}{{1000}}}}{V}}}$
After cancelling the term 9.8 and $V$ we get,
$h= \dfrac{10^8}{10^6}$
$\therefore h = 100$
If the ball is taken at a depth of $100{\text{ }}m$ then the volume of the rubber ball will be decreased by $0.1\% $.
Hence, the correct answer is option C.
Note: It must be noted that the bulk modulus or incompressibility is a negative value because the volume of the material gets decreased than its initial volume. It is actually the ratio of amount of bulk stress to bulk strain. Bulk stress is pressure as pressure is the force that is applied upon a particular area. Bulk strain is changed in volume to original volume.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Trending doubts
1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

Explain zero factorial class 11 maths CBSE
