Answer
Verified
389.4k+ views
Hint: Boron is the element of group 13. It has 3 valence electrons in its outer shell. On the basis of hybridization, the structure is estimated. The structure helps in finding the bond angle. The number of lone pairs should also be considered.
Complete answer:
Boron is the first element of the group 13.
Its outer electronic configuration is \[2{{s}^{2}}2{{p}^{1}}\]
It means that it has 3 valence electrons in its outer shell. Hence, it can form 3 bonds.
Now, in \[BC{{l}_{3}}\], boron is surrounded by 3 atoms of chlorine. Chlorine atom belongs to the group of halogens (group 17), which requires only one electron to complete its octet.
Hence, the chlorine forms a single bond with the boron atom.
Now, all the 3 valence electrons of boron form a bond with the chlorine atom hence there are no lone pairs present in the compound.
Since there are 3 bonds in the compound the hybridization will be \[s{{p}^{2}}\]
And we know that \[s{{p}^{2}}\] hybridization forms trigonal planar geometry.
The trigonal planar has \[{{120}^{\circ }}\] bond angle around the central atom.
Now, in \[B{{F}_{3}}\], boron is surrounded by 3 atoms of Fluorine. Fluorine atoms also belong to the group of halogens (group 17), which requires only one electron to complete its octet.
Hence, the chlorine forms a single bond with the boron atom.
Now, all the 3 valence electrons of boron form a bond with the Fluorine atom hence there is no lone pair present in the compound.
Since there are 3 bonds in the compound the hybridization will be \[s{{p}^{2}}\]
And we know that \[s{{p}^{2}}\] hybridization forms trigonal planar geometry.
The trigonal planar has \[{{120}^{\circ }}\] bond angle around the central atom.
Hence the bond angle is the same in both cases.
Note: You may get confused that fluorine is a more electronegative atom so it would make a bond angle different from boron trichloride. The structure and bond angle depends on the number of bonds and the number of lone pairs around the central atom.
Complete answer:
Boron is the first element of the group 13.
Its outer electronic configuration is \[2{{s}^{2}}2{{p}^{1}}\]
It means that it has 3 valence electrons in its outer shell. Hence, it can form 3 bonds.
Now, in \[BC{{l}_{3}}\], boron is surrounded by 3 atoms of chlorine. Chlorine atom belongs to the group of halogens (group 17), which requires only one electron to complete its octet.
Hence, the chlorine forms a single bond with the boron atom.
Now, all the 3 valence electrons of boron form a bond with the chlorine atom hence there are no lone pairs present in the compound.
Since there are 3 bonds in the compound the hybridization will be \[s{{p}^{2}}\]
And we know that \[s{{p}^{2}}\] hybridization forms trigonal planar geometry.
The trigonal planar has \[{{120}^{\circ }}\] bond angle around the central atom.
Now, in \[B{{F}_{3}}\], boron is surrounded by 3 atoms of Fluorine. Fluorine atoms also belong to the group of halogens (group 17), which requires only one electron to complete its octet.
Hence, the chlorine forms a single bond with the boron atom.
Now, all the 3 valence electrons of boron form a bond with the Fluorine atom hence there is no lone pair present in the compound.
Since there are 3 bonds in the compound the hybridization will be \[s{{p}^{2}}\]
And we know that \[s{{p}^{2}}\] hybridization forms trigonal planar geometry.
The trigonal planar has \[{{120}^{\circ }}\] bond angle around the central atom.
Hence the bond angle is the same in both cases.
Note: You may get confused that fluorine is a more electronegative atom so it would make a bond angle different from boron trichloride. The structure and bond angle depends on the number of bonds and the number of lone pairs around the central atom.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred
What is the stopping potential when the metal with class 12 physics JEE_Main
The momentum of a photon is 2 times 10 16gm cmsec Its class 12 physics JEE_Main
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
Trending doubts
How do you solve x2 11x + 28 0 using the quadratic class 10 maths CBSE
Which type of bond is stronger ionic or covalent class 12 chemistry CBSE
What organs are located on the left side of your body class 11 biology CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Difference Between Plant Cell and Animal Cell
How fast is 60 miles per hour in kilometres per ho class 10 maths CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
When people say No pun intended what does that mea class 8 english CBSE