
The area of a triangular region is 12,692 m\[^2\]. The perpendicular from one vertex to the opposite side is 76 m. Find the length of this side.
Answer
509.1k+ views
Hint:
First, we will find the dimension of the triangle. Then use the formula of area of the triangle is \[A = \dfrac{1}{2}bh\], where \[b\] is the base of the triangle and \[h\] is the height of the triangle. Apply this formula of area of a triangle, and then use the given conditions to find the required value.
Complete step by step solution:
It is given that the area \[A\] of triangular region \[{\text{ABC}}\] is 12,692 m\[^2\] and the height of this triangle is 76 m.
Let us assume that the breadth of the triangular region is \[b\] m.
We will now draw the triangle ABC using the given condition.
We know that the area of the triangle is calculated as \[A = \dfrac{1}{2}bh\], where \[b\] is the base of the triangle and \[h\] is the height of the triangle.
We will now substitute the value of the area \[A\] of the triangle \[{\text{ABC}}\] and the height of the triangle \[h\] in the above formula.
\[
12,692 = \dfrac{1}{2} \times b \times 76 \\
\Rightarrow 12,692 = 38b \\
\]
Dividing the above equation by 38 into each of the sides to find the base of the triangular region, we get
\[
\Rightarrow \dfrac{{12,692}}{{38}} = \dfrac{{38b}}{{38}} \\
\Rightarrow b = 334{\text{ cm}} \\
\]
Thus, the base of the triangular region is 334 cm.
Note:
In solving these types of questions, first draw the pictorial representation of the given problem for better understanding. Some students use the formula of area of the triangle is \[Area = \sqrt {s\left( {s - a} \right)\left( {s - b} \right)\left( {s - c} \right)} \], where \[s\] is the semi perimeter of the triangle and \[a\], \[b\] and \[c\] are the sides of the triangle instead of the one we used, which is wrong. Since we are given in the question that there is a perpendicular from one vertex implies that the formula, \[A = \dfrac{1}{2}bh\], where \[b\] is the base of the triangle and \[h\] is the height of the triangle will be used for finding the area of triangle.
First, we will find the dimension of the triangle. Then use the formula of area of the triangle is \[A = \dfrac{1}{2}bh\], where \[b\] is the base of the triangle and \[h\] is the height of the triangle. Apply this formula of area of a triangle, and then use the given conditions to find the required value.
Complete step by step solution:
It is given that the area \[A\] of triangular region \[{\text{ABC}}\] is 12,692 m\[^2\] and the height of this triangle is 76 m.
Let us assume that the breadth of the triangular region is \[b\] m.
We will now draw the triangle ABC using the given condition.

We know that the area of the triangle is calculated as \[A = \dfrac{1}{2}bh\], where \[b\] is the base of the triangle and \[h\] is the height of the triangle.
We will now substitute the value of the area \[A\] of the triangle \[{\text{ABC}}\] and the height of the triangle \[h\] in the above formula.
\[
12,692 = \dfrac{1}{2} \times b \times 76 \\
\Rightarrow 12,692 = 38b \\
\]
Dividing the above equation by 38 into each of the sides to find the base of the triangular region, we get
\[
\Rightarrow \dfrac{{12,692}}{{38}} = \dfrac{{38b}}{{38}} \\
\Rightarrow b = 334{\text{ cm}} \\
\]
Thus, the base of the triangular region is 334 cm.
Note:
In solving these types of questions, first draw the pictorial representation of the given problem for better understanding. Some students use the formula of area of the triangle is \[Area = \sqrt {s\left( {s - a} \right)\left( {s - b} \right)\left( {s - c} \right)} \], where \[s\] is the semi perimeter of the triangle and \[a\], \[b\] and \[c\] are the sides of the triangle instead of the one we used, which is wrong. Since we are given in the question that there is a perpendicular from one vertex implies that the formula, \[A = \dfrac{1}{2}bh\], where \[b\] is the base of the triangle and \[h\] is the height of the triangle will be used for finding the area of triangle.
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