
The area of a square plot is 6084 $m^2$. Find the length of the wire which can go four times along the boundary of the plot.
Answer
511.2k+ views
Hint: Since the area is given to us, we will find out the side of the square plot and after that we have to find the length of the wire which can go four times the boundary of the square plot that means we have to find the perimeter of the square and multiply it by 4.
Complete step-by-step answer:
We are given the area of the square = 6084 $m^2$
Let the side of the square be x m
We know that the area of the square = ${side}^2$
Using the above formula, we will find the side of the square plot as follows:
Area = $side \times side$
$6084 = x \times x$
$6084 = {x^2}$
$x = \sqrt {6084} $
On solving, we get
X = 78 m
Therefore side of the square plot = 78 m
Now, we will find the perimeter of the square plot to find the length of the wire.
Perimeter= $4 \times side$
We have side = 78 m
Perimeter = $4 \times 78$= 312m
This means 1 round of wire will require 312 m of wire but we need four rounds of wire,
So, the total length of wire required for four rounds = $4 \times 312$= 1248m
Note: Since we know that the area of a square is Area =$side \times side$, using this formula we will find the side of the square. After that we will find the perimeter of the square the formula of which is Perimeter = $4 \times side$. Once we have the perimeter , we can find the length of the wire which can go for 4 times along the boundary.
Complete step-by-step answer:

We are given the area of the square = 6084 $m^2$
Let the side of the square be x m
We know that the area of the square = ${side}^2$
Using the above formula, we will find the side of the square plot as follows:
Area = $side \times side$
$6084 = x \times x$
$6084 = {x^2}$
$x = \sqrt {6084} $
On solving, we get
X = 78 m
Therefore side of the square plot = 78 m
Now, we will find the perimeter of the square plot to find the length of the wire.
Perimeter= $4 \times side$
We have side = 78 m
Perimeter = $4 \times 78$= 312m
This means 1 round of wire will require 312 m of wire but we need four rounds of wire,
So, the total length of wire required for four rounds = $4 \times 312$= 1248m
Note: Since we know that the area of a square is Area =$side \times side$, using this formula we will find the side of the square. After that we will find the perimeter of the square the formula of which is Perimeter = $4 \times side$. Once we have the perimeter , we can find the length of the wire which can go for 4 times along the boundary.
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