The area of a rectangle remains the same if the length is increased by 7 meters and the breadth is decreased by 3 meters. The area remains unaffected if the length is decreased by 7 meters and breadth is increased by 5 meters. Find the dimensions of the rectangle.
Answer
643.8k+ views
Hint - We will start by assuming two variables as x and y then make two different equations by using the information which is mentioned in the question then after solving those equations we will find the required values of x and y.
Complete step-by-step answer:
It is given that the area of a rectangle remains the same when the length is increased by 7 meters and the breadth is decreased by 3 meters and the area remains unaffected when the length is decreased by 7 meters and breadth is increased by 5 meters, so by using this we can make two different equations.
For which, let the length of the rectangle be $x$ units and the breadth be $y$ units.
We know that,
Area of the rectangle = Length $ \times $ Breadth
$ = x \times y$
$ = xy$ sq. units
Now, we will make equations from the given information.
According to first case the equation will be,
$\left( {x + 7} \right) \times \left( {y - 3} \right) = xy$……… (1)
And, according to the second case the equation will be,
$\left( {x - 7} \right) \times \left( {y + 5} \right) = xy$ ……... (2)
Taking equation (1),
$\left( {x + 7} \right) \times \left( {y - 3} \right) = xy$
$
\Rightarrow xy - 3x + 7y - 21 = xy \\
\Rightarrow - 3x + 7y - 21 = 0 \\
\Rightarrow - 3x + 7y = 21 \\
$
$ \Rightarrow 7y - 3x = 21$ …………. (i)
Now, taking equation (2),
$\left( {x - 7} \right) \times \left( {y + 5} \right) = xy$
$
\Rightarrow xy + 5x - 7y - 35 = xy \\
\Rightarrow 5x - 7y = 35 \\
$
$ \Rightarrow - 7y + 5x = 35$ …………. (ii)
Adding (i) and (ii), we get
$7y - 3x = 21$
$ - 7y + 5x = 35$
$\overline {0 + 2x = 56} $
$
2x = 56 \\
x = \dfrac{{56}}{2} \\
x = 28 \\
$
Putting $x = 28$ in equation (i), we get,
$
7y - 3\left( {28} \right) = 21 \\
\Rightarrow 7y - 84 = 21 \\
\Rightarrow 7y = 21 + 84 \\
\Rightarrow 7y = 105 \\
\Rightarrow y = \dfrac{{105}}{7} \\
\Rightarrow y = 15 \\
$
Hence, length of the rectangle $ = x = 28$m
and, breadth of the rectangle $ = y = 15$m
Note - A rectangle is a quadrilateral with four straight sides and four right angles. It has unequal adjacent sides, in contrast to a square. These kinds of questions are very simple and easy to solve if one understands the question properly and knows how to solve the equations.
Complete step-by-step answer:
It is given that the area of a rectangle remains the same when the length is increased by 7 meters and the breadth is decreased by 3 meters and the area remains unaffected when the length is decreased by 7 meters and breadth is increased by 5 meters, so by using this we can make two different equations.
For which, let the length of the rectangle be $x$ units and the breadth be $y$ units.
We know that,
Area of the rectangle = Length $ \times $ Breadth
$ = x \times y$
$ = xy$ sq. units
Now, we will make equations from the given information.
According to first case the equation will be,
$\left( {x + 7} \right) \times \left( {y - 3} \right) = xy$……… (1)
And, according to the second case the equation will be,
$\left( {x - 7} \right) \times \left( {y + 5} \right) = xy$ ……... (2)
Taking equation (1),
$\left( {x + 7} \right) \times \left( {y - 3} \right) = xy$
$
\Rightarrow xy - 3x + 7y - 21 = xy \\
\Rightarrow - 3x + 7y - 21 = 0 \\
\Rightarrow - 3x + 7y = 21 \\
$
$ \Rightarrow 7y - 3x = 21$ …………. (i)
Now, taking equation (2),
$\left( {x - 7} \right) \times \left( {y + 5} \right) = xy$
$
\Rightarrow xy + 5x - 7y - 35 = xy \\
\Rightarrow 5x - 7y = 35 \\
$
$ \Rightarrow - 7y + 5x = 35$ …………. (ii)
Adding (i) and (ii), we get
$7y - 3x = 21$
$ - 7y + 5x = 35$
$\overline {0 + 2x = 56} $
$
2x = 56 \\
x = \dfrac{{56}}{2} \\
x = 28 \\
$
Putting $x = 28$ in equation (i), we get,
$
7y - 3\left( {28} \right) = 21 \\
\Rightarrow 7y - 84 = 21 \\
\Rightarrow 7y = 21 + 84 \\
\Rightarrow 7y = 105 \\
\Rightarrow y = \dfrac{{105}}{7} \\
\Rightarrow y = 15 \\
$
Hence, length of the rectangle $ = x = 28$m
and, breadth of the rectangle $ = y = 15$m
Note - A rectangle is a quadrilateral with four straight sides and four right angles. It has unequal adjacent sides, in contrast to a square. These kinds of questions are very simple and easy to solve if one understands the question properly and knows how to solve the equations.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

Who Won 36 Oscar Awards? Record Holder Revealed

Why is it 530 pm in india when it is 1200 afternoon class 10 social science CBSE

What is the full form of POSCO class 10 social science CBSE

Define Potential, Developed, Stock and Reserved resources

The speaker of the Lok Sabha is elected by the APresident class 10 social science CBSE

