
The approximate atomic weight of electron or positron per mole is:
\[
A.{\text{ }}5.48 \times {10^{ - 6}}gmo{l^{ - 1}} \\
B.{\text{ }}5.48 \times {10^{ - 8}}gmo{l^{ - 1}} \\
C.{\text{ }}5.48 \times {10^{ - 4}}gmo{l^{ - 1}} \\
D.{\text{ None of these}} \\
\]
Answer
619.2k+ views
Hint- In order to find the atomic weight of electron, first we will understand the basic definition of electron then we will proceed further by multiplying the mass of electron by Avogadro's number in order to find the atomic weight of electron or positron per mole.
Complete answer:
Electron : An electron is a negatively charged subatomic particle. It can be either free (not attached to any atom), or bound to the nucleus of an atom. Electrons in atoms exist in spherical shells of various radii, representing energy levels. The charge on a single electron is considered as the unit electrical charge.
As we know that
Mass of one electron $ = 9.1 \times {10^{ - 27}}g$
As we know that one mole of electrons contains Avagadro’s number of electrons.
So, mass of one mole of electron $ = m \times Na$ --- (1)
Where m is the mass of each electron and Na is the Avagadro’s number which is equal to $6.023 \times {10^{23}}$
So let us now substitute the values in equation (1) to find the atomic weight of electrons per mole.
Mass of one mole of electron:
$
= m \times Na \\
= 9.1 \times {10^{ - 27}}g \times 6.023 \times {10^{23}} \\
= 5.48093 \times {10^{ - 4}}g/mol \\
\simeq 5.48 \times {10^{ - 4}}gmo{l^{ - 1}} \\
$
Hence, the approximate atomic weight of electron or positron per mole is $5.48 \times {10^{ - 4}}gmo{l^{ - 1}}$
So, the correct answer is option C.
Note- The mole is the unit of measurement for the amount of substance in the International System of Units. A mole of a substance or a mole of particles is defined as exactly $6.023 \times {10^{23}}$ particles, which may be atoms, molecules, ions, or electrons. This number is called Avagadro’s number. Students must remember the value of Avagadro’s number to solve such problems related to mole concept.
Complete answer:
Electron : An electron is a negatively charged subatomic particle. It can be either free (not attached to any atom), or bound to the nucleus of an atom. Electrons in atoms exist in spherical shells of various radii, representing energy levels. The charge on a single electron is considered as the unit electrical charge.
As we know that
Mass of one electron $ = 9.1 \times {10^{ - 27}}g$
As we know that one mole of electrons contains Avagadro’s number of electrons.
So, mass of one mole of electron $ = m \times Na$ --- (1)
Where m is the mass of each electron and Na is the Avagadro’s number which is equal to $6.023 \times {10^{23}}$
So let us now substitute the values in equation (1) to find the atomic weight of electrons per mole.
Mass of one mole of electron:
$
= m \times Na \\
= 9.1 \times {10^{ - 27}}g \times 6.023 \times {10^{23}} \\
= 5.48093 \times {10^{ - 4}}g/mol \\
\simeq 5.48 \times {10^{ - 4}}gmo{l^{ - 1}} \\
$
Hence, the approximate atomic weight of electron or positron per mole is $5.48 \times {10^{ - 4}}gmo{l^{ - 1}}$
So, the correct answer is option C.
Note- The mole is the unit of measurement for the amount of substance in the International System of Units. A mole of a substance or a mole of particles is defined as exactly $6.023 \times {10^{23}}$ particles, which may be atoms, molecules, ions, or electrons. This number is called Avagadro’s number. Students must remember the value of Avagadro’s number to solve such problems related to mole concept.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
Draw a diagram of nephron and explain its structur class 11 biology CBSE

Explain zero factorial class 11 maths CBSE

Chemical formula of Bleaching powder is A Ca2OCl2 B class 11 chemistry CBSE

Name the part of the brain responsible for the precision class 11 biology CBSE

The growth of tendril in pea plants is due to AEffect class 11 biology CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

