
The angular velocity ( in $rad/s$ ) of a body rotating at $N$ rpm is
$A.\dfrac{\pi N}{60}$
$B.\dfrac{2\pi N}{60}$
$C.\dfrac{\pi N}{120}$
$D.\dfrac{\pi N}{180}$
Answer
556.5k+ views
Hint: We will use the relationship of angular velocity and revolution per minute (rpm). Angular velocity is defined as the angular displacement per unit time. Revolution made in one minute is termed as the revolution per minute.
Formula Used:
We are going to use the following formula to solve the problem:-
$\omega =\dfrac{2\pi }{T}$
Complete answer:
Suppose a body is rotating with angular velocity, $\omega $in time $T$ seconds then its angular velocity is given as follows:-
$\omega =\dfrac{2\pi }{T}$ …………. $(i)$
We have to find in revolution per minute and we know that $1\min =60s$, then equation $(i)$ becomes
$\omega =\dfrac{2\pi }{60}$ …………….. $(ii)$
For $N$ number of revolutions this equation $(ii)$ becomes
$\omega =\dfrac{2\pi N}{60}rad/s$
Hence, option $(B)$ is correct.
Additional Information:
Angular velocity is defined as the angular displacement per unit time. It is generally represented with the help of a Greek letter which is known as omega ( $\Omega $ ). It tells how fast the angular position of an object changes with respect to time. The SI unit of angular velocity is radians per second. By convention, positive angular velocity is indicated with anti-clockwise rotation while negative angular velocity is indicated with clockwise rotation. If the angles are measured in radians then linear velocity is the product of angular velocity and the radius. Revolution per minute is the number of turns in one minute. It is also used to represent the angular speed.
Note:
We should give our attention towards the fact that radians per second and revolution per minute are different units to represent angular velocity or speed. Conversion of minutes into seconds or vice versa should also be taken care of. Correct use of relations should be applied.
Formula Used:
We are going to use the following formula to solve the problem:-
$\omega =\dfrac{2\pi }{T}$
Complete answer:
Suppose a body is rotating with angular velocity, $\omega $in time $T$ seconds then its angular velocity is given as follows:-
$\omega =\dfrac{2\pi }{T}$ …………. $(i)$
We have to find in revolution per minute and we know that $1\min =60s$, then equation $(i)$ becomes
$\omega =\dfrac{2\pi }{60}$ …………….. $(ii)$
For $N$ number of revolutions this equation $(ii)$ becomes
$\omega =\dfrac{2\pi N}{60}rad/s$
Hence, option $(B)$ is correct.
Additional Information:
Angular velocity is defined as the angular displacement per unit time. It is generally represented with the help of a Greek letter which is known as omega ( $\Omega $ ). It tells how fast the angular position of an object changes with respect to time. The SI unit of angular velocity is radians per second. By convention, positive angular velocity is indicated with anti-clockwise rotation while negative angular velocity is indicated with clockwise rotation. If the angles are measured in radians then linear velocity is the product of angular velocity and the radius. Revolution per minute is the number of turns in one minute. It is also used to represent the angular speed.
Note:
We should give our attention towards the fact that radians per second and revolution per minute are different units to represent angular velocity or speed. Conversion of minutes into seconds or vice versa should also be taken care of. Correct use of relations should be applied.
Recently Updated Pages
Why is there a time difference of about 5 hours between class 10 social science CBSE

In cricket, what is a "pink ball" primarily used for?

In cricket, what is the "new ball" phase?

In cricket, what is a "death over"?

What is the "Powerplay" in T20 cricket?

In cricket, what is a "super over"?

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

Which animal has three hearts class 11 biology CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

