Question

The amplitude of electric and magnetic fields related to each other are
A) ${{\text{E}}_{\text{o}}}\,\text{=}\,{{\text{B}}_{\text{o}}}$
B) ${{\text{E}}_{\text{o}}}\,\text{=}\,\text{C}{{\text{B}}_{\text{o}}}$
C) ${{\text{E}}_{\text{o}}}\,\text{=}\,\dfrac{{{\text{B}}_{\text{o}}}}{\text{C}}$
D) ${{\text{E}}_{\text{o}}}\,\text{=}\,\dfrac{\text{C}}{{{\text{B}}_{\text{o}}}}$

Answer 1

Hint
We can remember here that Maxwell was able to establish the property that a wave maximum of the magnetic field always coincides with a wave maximum of the electric field in both time and space. Also the amplitude of the electric field is directly proportional to magnetic field.

Complete Step By Step Solution
We see that the electric field is always perpendicular to the magnetic field, and both are directed at right angles to the direction of propagation of the wave. In fact the wave propagates in the direction EXB. Electromagnetic waves are clearly a type of transverse wave. Electromagnetic Waves are self propagating transverse waves.
As mentioned the electric and magnetic field are directly proportional.
$\begin{align}
  & \therefore \,{{\text{E}}_{\text{o}\,}}\,\text{ }\!\!\alpha\!\!\text{ }\,{{\text{B}}_{\text{o}}} \\
 & \Rightarrow \,{{\text{E}}_{\text{o}}}\,\text{=}\,\text{C}{{\text{B}}_{\text{o}}} \\
\end{align}$
Hence the answer Is option (B).

Note Also these Is no constraint on the possible frequency of electromagnetic waves wavelength of electromagnetic waves, speed of traveling in free space with velocity of light and it takes the value,
$\text{C}\,\text{=}\,\dfrac{\text{1}}{\sqrt{{\text{μ}}_{\text{o}}}\sqrt{{\in }_{\text{o}}}}$
Here, $μ_0$ is called absolute permeability. It’s value is $1.257×{10}^{−6}Tm{A}^{−1}$
$ϵ_0$ is called absolute permittivity. It’s value is $8.854 \times 10^{−12}C^2N^{−1}m^{−2}$
$C$ is the velocity of light in vacuum = velocity of electromagnetic waves in free space = $3 \times 10^8 ms^{−1}$.