Question

The above reaction is ionization or dissociation?
$NaCl\, \to N{a^ + }\, + \,C{l^ - }$
A.Dissociation
B.Ionization
C.Both ionization and dissociation
D.None of the above

Answer 1

Hint:Generally, a metal loses the ion and nonmetal gain to become stable. It loses or gains one or two ions. An element has a plus sign ion means it loses or donate the electron. Other hands, If the element has a minus sign means it gains the electron.

Complete step by step answer:
According to the question, we have
$NaCl\, \to N{a^ + }\, + \,C{l^ - }$
Here, $NaCl$ - Sodium chloride
$N{a^ + }$ - sodium
$C{l^ - }$ - chlorine
When sodium chloride dissolves in water, it will split. And then sodium and chlorine separated. It is split into two parts because water is a polar molecule.
Polar Molecule-A molecule has one side is a positive charge, and the other is a negative charge is known as a polar molecule. It has a polar bond that ranges between $2.0$$ - $ $0.5$.
Bond - The connection between two atoms due to a bond that happens due to electrostatic force.
One polar molecule easily dissolves in another. Therefore, sodium chloride easily dissolves with water in water.
So, $N{a^ + }$ attracts towards ${O^ - }$ and $C{l^ - }$ is attracted towards ${H^ + }$.
The separation of ions is called dissociation. So that's why here option A is the correct answer.

Additional Information: Dipole moment is one of the important properties of a polar molecule. It shows the distance between positive and negative charges. SI unit of dipole moment is.

Note:
In chemistry, a positive ion is also known as Cation and a negative ion is also called Anion. Opposite ions always attract. Electronegativity helps to attract an atom. Oxygen has 3.22 and Hydrogen has 2.20.