
The $100\,g$ of an iron ball having velocity \[10{\text{ }}m{s^{ - 1}}\] collides with a wall at an angle $30^\circ $ and rebounds with the same angle. if the period of contact between the ball and wall is 0.1 second, then the force experienced by the ball is
A. 10 N
B. 100 N
C. 1 N
D. 0.1 N
Answer
498.3k+ views
Hint:in order to solve the question, we will formula of rate of change in momentum and to apply that we will make the diagram so as to see the pictorial representation of resolving the components of momentum after the resolving we will apply the momentum in formula along with the time and get the answer
Formula used:
Force =rate of change in momentum
$F = \dfrac{{M \times V}}{T}$
Here, $F$ refers to force, $M$ refers to mass, $V$ refers to velocity and $T$ refers to time period.
Complete step by step answer:
In the question we are an iron ball which collides with a wall and rebounds with the same angle and we have to find the force experienced by the ball.
Mass of iron ball = 100 g
Velocity of iron ball = \[10{\text{ }}m{s^{ - 1}}\] collides with a wall
Ball collides the wall at an angle = $30^\circ $
period of contact between the ball and wall = 0.1 s
This diagram shows how the ball collides with the wall and then rebound at an angle of $30^\circ $. Now we resolve the vertical and horizontal component; the horizontal component will add up \[mv\sin \theta + mv\sin \theta \] while the component $mv\cos \theta $ will cancel out.
This diagram shows the resolved component, now the change in momentum will be $2mv\sin \theta $ which is the product of mass and velocity. Applying the formula
$F = \dfrac{{M \times V}}{T}$
$M \times V = 2mv\sin \theta $
$\theta = 30^\circ $ and T = 0.1 s as given in the question
Now substituting the values in the equation
$F = \dfrac{{M \times V}}{T}$
$ \Rightarrow F = \dfrac{{2mv\sin 30^\circ }}{{0.1}}$
$ \Rightarrow F = \dfrac{{2 \times 0.1 \times 10 \times \sin 30^\circ }}{{0.1}}$
We have converted mass from g to kg
$ \Rightarrow F = \dfrac{{2 \times 0.1 \times 10 \times 0.5}}{{0.1}}N$
$ \Rightarrow F = 10{\text{ }}N$
Therefore, the force experienced by the ball is $10{\text{ }}N$.
Hence the correct option is A.
Note: Many of the students will make the mistake by not taking the physical quantities in their SI unit especially in this question we are given the mass of iron ball 100g and we have to convert into kg so that the force which comes out would remain in newton along with this we also have use diagram as to make question simple.
Formula used:
Force =rate of change in momentum
$F = \dfrac{{M \times V}}{T}$
Here, $F$ refers to force, $M$ refers to mass, $V$ refers to velocity and $T$ refers to time period.
Complete step by step answer:
In the question we are an iron ball which collides with a wall and rebounds with the same angle and we have to find the force experienced by the ball.
Mass of iron ball = 100 g
Velocity of iron ball = \[10{\text{ }}m{s^{ - 1}}\] collides with a wall
Ball collides the wall at an angle = $30^\circ $
period of contact between the ball and wall = 0.1 s
This diagram shows how the ball collides with the wall and then rebound at an angle of $30^\circ $. Now we resolve the vertical and horizontal component; the horizontal component will add up \[mv\sin \theta + mv\sin \theta \] while the component $mv\cos \theta $ will cancel out.
This diagram shows the resolved component, now the change in momentum will be $2mv\sin \theta $ which is the product of mass and velocity. Applying the formula
$F = \dfrac{{M \times V}}{T}$
$M \times V = 2mv\sin \theta $
$\theta = 30^\circ $ and T = 0.1 s as given in the question
Now substituting the values in the equation
$F = \dfrac{{M \times V}}{T}$
$ \Rightarrow F = \dfrac{{2mv\sin 30^\circ }}{{0.1}}$
$ \Rightarrow F = \dfrac{{2 \times 0.1 \times 10 \times \sin 30^\circ }}{{0.1}}$
We have converted mass from g to kg
$ \Rightarrow F = \dfrac{{2 \times 0.1 \times 10 \times 0.5}}{{0.1}}N$
$ \Rightarrow F = 10{\text{ }}N$
Therefore, the force experienced by the ball is $10{\text{ }}N$.
Hence the correct option is A.
Note: Many of the students will make the mistake by not taking the physical quantities in their SI unit especially in this question we are given the mass of iron ball 100g and we have to convert into kg so that the force which comes out would remain in newton along with this we also have use diagram as to make question simple.
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